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3 years ago

11

Balance this equation Pb(NO3)2+Na2(CrO4)=Pb(CtO4)+Na(NO3)

1 answer:

zzz [600]3 years ago

3 0

I'm guessing you mean Cr (Chromium) in the product instead of Ct.

<span>Pb(NO3)2 + Na2(CrO4) = Pb(CtO4) + 2Na(NO3)</span>

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When an object falls to the ground, potential energy is most likely transformed into

pentagon [3]

Answer:

kinetic energy

Explanation:

When the object is released, the gravitational potential energy is gradually converted into kinetic energy as it picks up speed.

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3 years ago

Help help with the question below

mestny [16]

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2 years ago

11. If four gases in a cylinder each exert 6 atm, what is the total pressure exerted by the

Debora [2.8K]

Answer:

24 atm is the total pressure exerted by the gases

Explanation:

We propose this situation:

In a vessel, we have 4 gases (for example, hydrogen, Xe, methane and chlorine)

Each of the gases has the same pressure:

6 atm → hydrogen

6 atm → xenon

6 atm → methane

6 atm → chlorine

To determine the total pressure, we sum all of them:

Partial pressure H₂ + Partial pressure Xe + Partial pressure CH₄ + Partial pressure Cl₂ = Total P

6 atm + 6 atm + 6 atm + 6 atm = 24atm

8 0

3 years ago

Aclosed system contains an equimolar mixture of n-pentane and isopentane. Suppose the system is initially all liquid at 120°C an

garri49 [273]

Explanation:

The given data is as follows.

T = $120^{o}C$ = (120 + 273.15)K = 393.15 K,

As it is given that it is an equimolar mixture of n-pentane and isopentane.

So, $x_{1}$ = 0.5 and $x_{2}$ = 0.5

According to the Antoine data, vapor pressure of two components at 393.15 K is as follows.

$p^{sat}_{1}$ (393.15 K) = 9.2 bar

$p^{sat}_{1}$ (393.15 K) = 10.5 bar

Hence, we will calculate the partial pressure of each component as follows.

$p_{1} = x_{1} \times p^{sat}_{1}$

= $0.5 \times 9.2 bar$

= 4.6 bar

and, $p_{2} = x_{2} \times p^{sat}_{2}$

= $0.5 \times 10.5 bar$

= 5.25 bar

Therefore, the bubble pressure will be as follows.

P = $p_{1} + p_{2}$

= 4.6 bar + 5.25 bar

= 9.85 bar

Now, we will calculate the vapor composition as follows.

$y_{1} = \frac{p_{1}}{p}$

= $\frac{4.6}{9.85}$

= 0.467

and, $y_{2} = \frac{p_{2}}{p}$

= $\frac{5.25}{9.85}$

= 0.527

Calculate the dew point as follows.

$y_{1}$ = 0.5, $y_{2}$ = 0.5

$\frac{1}{P} = \sum \frac{y_{1}}{p^{sat}_{1}}$

$\frac{1}{P} = \frac{0.5}{9.2} + \frac{0.5}{10.2}$

$\frac{1}{P}$ = 0.101966 $bar^{-1}$

P = 9.807

Composition of the liquid phase is $x_{i}$ and its formula is as follows.

$x_{i} = \frac{y_{i} \times P}{p^{sat}_{1}}$

= $\frac{0.5 \times 9.807}{9.2}$

= 0.5329

$x_{z} = \frac{y_{i} \times P}{p^{sat}_{1}}$

= $\frac{0.5 \times 9.807}{10.5}$

= 0.467

4 0

3 years ago

Iodine-131 is used to

Yakvenalex [24]

Iodine 131 is a radioisotope with a very short half-life of 8.02 days, making it highly radioactive. Frequently used in small doses in thyroid cancers therapies, it is also one of the most feared fission products when accidentally released into the environment. Radiotoxicity of iodine 131.

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3 years ago