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velikii [3]
3 years ago
5

Why does it hurt your hands when you carry heavy shopping in carrier bags?

Physics
2 answers:
Elodia [21]3 years ago
8 0
I think it is when the plastic is wrap tight in your hand it makes them fell sore
PilotLPTM [1.2K]3 years ago
8 0
It hurts your hands because the handle of the carrier bag cuts into your skin
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Ezra is pulling a sled, filled with snow, by pulling on a rope attached to the sled. The rope makes an angle θ with respect to t
svetoff [14.1K]

Answer:

Explanation:

Given

rope makes an angle of \theta

Mass of sled and snow is m

Normal Force =F_N

applied Force is F

as Force is pulling in nature therefore normal reaction is given by

F_N=mg-F\sin \theta

Also F\cos \theta =f_r

f_r=\mu _k\cdot F_N

f_r=\mu _k\cdot (mg-F\sin \theta )

F\cos \theta =\mu _kF_N-------1

F\sin \theta =mg-F_N---------2

Squaring 1 & 2 and then adding

F^2=(\mu _kF_N)^2+(mg-F_N)^2

F=\sqrt{(\mu _kF_N)^2+(mg-F_N)^2}

Substitute value of F in 1

cos\theta =\frac{\mu _KF_N}{\sqrt{(\mu _kF_N)^2+(mg-F_N)^2}}

\theta =cos^{-1}(\frac{\mu _KF_N}{\sqrt{(\mu _kF_N)^2+(mg-F_N)^2}})

8 0
3 years ago
What is the correct answer?
sashaice [31]

Answer:

D) 4

Explanation:

Roots of a polynomial must be factors of the last term.

In this case, the factors of 6 are +1, -1, +2, -2, +3, -3, +6, -6. The only factor that doesn't show up, given the options, is 4. This means that D is the correct answer.

7 0
3 years ago
A 1.0-kg block moving to the right at speed 3.0 m/s collides with an identical block also moving to the right at a speed 1.0 m/s
____ [38]

Answer:

Speed of both blocks after collision is 2 m/s

Explanation:

It is given that,

Mass of both blocks, m₁ = m₂ = 1 kg

Velocity of first block, u₁ = 3 m/s

Velocity of other block, u₂ = 1 m/s

Since, both blocks stick after collision. So, it is a case of inelastic collision. The momentum remains conserved while the kinetic energy energy gets reduced after the collision. Let v is the common velocity of both blocks. Using the conservation of momentum as :

m_1u_1+m_2u_2=(m_1+m_2)v

v=\dfrac{m_1u_1+m_2u_2}{(m_1+m_2)}

v=\dfrac{1\ kg\times 3\ m/s+1\ kg\times 1\ m/s}{2\ kg}

v = 2 m/s

Hence, their speed after collision is 2 m/s.

7 0
3 years ago
What does the pupil of the eye controls
Alja [10]
The correct answer would be D
5 0
4 years ago
Kepler's 3rd law: harmonic law
Amanda [17]
<span>orbital velocities to their mean distances from the Sun.</span>
7 0
3 years ago
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