Distance is 50 km
Displacement is 10 km
<u>Explanation:</u>
Given:
Distance toward south, x = 25 km
Distance towards west, y = 10 km
Distance towards north, z = 15 km
(a) Total distance, D = ?
Total distance, D = x + y + z
D = 25 + 10 + 15
D = 50km
(b) Displacement, d = ?
Displacement = final position - initial position
= 10 - 0 km
= 10km
sign out and log in again...if does not work then make a new account
Answer:
The force per unit length (N/m) on the top wire is 16.842 N/m
Explanation:
Given;
distance between the two parallel wire, d = 38 cm = 0.38 m
current in the first wire, I₁ = 4.0 kA
current in the second wire, I₂ = 8.0 kA
Force per unit length, between two parallel wires is given as;

where;
μ₀ is constant = 4π x 10⁻⁷ T.m/A
Substitute the given values in the above equation and calculate the force per unit length

Therefore, the force per unit length (N/m) on the top wire is 16.842 N/m
1. I think it's the trails left by an electron as it moves around the nucleus.
2. The atomic number is the number of protons so it is 8.
3. It's mass is lowered but it is still the same element.
Write a:
● Hypothesis
●Procedures
●Materials
●Data Table
●Conclusion
●Variables (Independent and dependent)
●Bibliography