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s344n2d4d5 [400]
3 years ago
11

1) Two objects will attract one another when they have ____. A) like charges. B) opposite charges. C) the same amount of charge.

D) no charge. 2) An electric field gets stronger as you ____. A) get closer to a charge. B) get farther from a charge. C) add electrons to a positively charged object. D) remove electrons from a negatively charged object
Physics
2 answers:
kykrilka [37]3 years ago
6 0
Two objects will attract one another when they have B. Opposite charges ,
which you can found on a magnet

An electric field gets stronger as you : A. Get closer to a charge
This happen because electric field exert influences to sensitive detectors in its surrounding area

hoe this helps

WARRIOR [948]3 years ago
3 0
1) Two objects will attract one another when they have ____. B) opposite charges. electric field gets stronger as you <span>get closer to a charge</span>
You might be interested in
Two strings are adjusted to vibrate at exactly 202 Hz. Then the tension in one string isincreased slightly. Afterward, three bea
Semenov [28]

The concepts necessary to solve this problem are framed in the expression of string vibration frequency as well as the expression of the number of beats per second conditioned at two frequencies.

Mathematically, the frequency of the vibration of a string can be expressed as

f = \frac{1}{2L}\sqrt{\frac{T}{\mu}}

Where,

L = Vibrating length string

T = Tension in the string

\mu = Linear mass density

At the same time we have the expression for the number of beats described as

n = |f_1-f_2|

Where

f_1 = First frequency

f_2 = Second frequency

From the previously given data we can directly observe that the frequency is directly proportional to the root of the mechanical Tension:

f \propto \sqrt{T}

If we analyze carefully we can realize that when there is an increase in the frequency ratio on the tight string it increases. Therefore, the beats will be constituted under two waves; one from the first string and the second as a residue of the tight wave, as well

n = f_2-f_1

f_2 = n+f_1

Replacing 3/sfor n and 202Hz for f_1,

f_2 = 3/s + 202Hz

f_2 = 3/s(\frac{1Hz}{1/s})+202Hz

f_2 = 206Hz

The frequency of the tightened is 205Hz

7 0
2 years ago
How would the terminal velocity of a piece of tissue paper compare to the terminal velocity of a rock?
matrenka [14]

Answer: Rock require larger drag force and to achieve it rock need to move at a very high terminal velocity.  

Explanation: Terminal velocity is defined as the final velocity attained by an object falling under the gravity. At this moment weight is balanced by the air resistance or drag force and body falls with zero acceleration i.e. with a constant velocity.

Case 1: Terminal velocity of a piece of tissue paper.

The weight of tissue paper is very less and it experiences an air resistance while falling downward under the effect of gravity.

Downward gravitational force, F = mg

Upward air resistance or friction or drag force will be f_{1}

So, paper will attain terminal velocity when mg =  f_{1}

Case 2: Rock is very heavy and require larger air resistance to balance the weight of rock relative to the tissue paper case.

Downward force on rock, F = Mg

Drag force = f_{2}

Rock will attain terminal velocity when Mg = f_{2}

Mg > mg

so, f_{2} > f_{1}

And rock require larger drag force and to achieve it rock need to move at a very high terminal velocity.  

5 0
3 years ago
PLEASE HELP! DUE DATE IS TODAY
g100num [7]

Answer:

<u>Question 2</u>

<u>Part (a)</u>

Chlorine:  type of compound = chloride

Oxygen:  type of compound = oxide

<u>Part (b)</u>

The iron reacts with water and oxygen to form rust.

A water molecule is made up of two hydrogen atoms joined to one oxygen atom:  Di-hydrogen oxide.

<u>Question 3</u>

This circuit is in parallel.

The current in a parallel circuit splits into different branches then combines again before it goes back into the supply.

We are told that A₁ = 0.8 A

As the lamps have <u>equal resistance</u>, the current splits equally:

A₂ = 0.4 A

A₃ = 0.4 A

Then combines again:

A₄ = 0.8 A

4 0
2 years ago
Two cars, initially at rest and 5 km apart at t=0 , simultaneously move toward each other. Car A travels at a constant speed of
Anastasy [175]

Answer:

<em>d. 268 s</em>

Explanation:

<u>Constant Speed Motion</u>

An object is said to travel at constant speed if the ratio of the distance traveled by the time taken is constant.

Expressed in a simple equation, we have:

\displaystyle v=\frac{d}{t}

Where  

v = Speed of the object

d = Distance traveled

t  = Time taken to travel d.

From the equation above, we can solve for d:

d = v . t

And we can also solve it for t:

\displaystyle t=\frac{d}{v}

Two cars are initially separated by 5 km are approaching each other at relative speeds of 55 km/h and 12 km/h respectively. The total speed at which they are approaching is 55+12 = 67 km/h.

The time it will take for them to meet is:

\displaystyle t=\frac{5}{67}

t = 0.0746 hours

Converting to seconds: 0.0746*3600 = 268.56

The closest answer is d. 268 s

8 0
3 years ago
1) How many AU make up a light-year?
MrRissso [65]

Answer:..

1.One light-year = 63,240 AU

2. It’s about 93 million miles (150 million km),or

one astronomical unit (AU) = 92,955,807 miles (149,597,871 km).

8 0
3 years ago
Read 2 more answers
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