Answer:
b. U = Q - W
Explanation:
Given;
change in internal energy, ΔU = 36 kJ
heat transferred to the surroundings Q = 14 kJ
Apply first law of thermodynamic; the change in internal energy is equal to heat added to the system minus work done by the system.
ΔU = Q - W
Since heat was lost to surroundings, Q = - Q
ΔU = (-Q) - W
36 kJ = -14 kJ - W
36 kJ + 14 kJ = - W
50 kJ = - W
W = - 50 kJ (the negative sign shows that work has been done on the system)
Thus, 50 kJ of work is done on the system.
The only correct answer in the given options is "b" U = Q-W
Answer:
An electron tube from which all air has been removed. The vacuum ensures transparency inside the tube for electric fields and moving electrons. Most electron tubes are vacuum tubes; cathode-ray tubes, which include television picture tubes and other video display tubes, are the most widely used vacuum tubes
Explanation:
hope it help
Answer:
Force on the proton will be 
Explanation:
We have given speed of proton is 20.3% of speed of light
Speed of light 
So speed of proton 
Magnetic field B = 0.00629 T
Charge on proton 
Angle between velocity and magnetic field 
Force on the proton is equal to 
The tension in the string when the ball is at the bottom of the path is 2.61 Newtons.
<h3>Tension</h3>
A tension is simply referred to as a force along the length of a flexible medium such as strings, cable, ropes etc.
Tension in a string revolving can be determined using the expression;
T = mv² / r
Where m is mass of object, v is velocity and r is radius ( length of string )
Given the data in the question;
- Radius ( length of string ) r = 97.7cm = 0.977m
- Tension in the string; T = ?
To determine tension in the string, we substitute our given values into the expression above.
T = mv² / r
T = (0.182kg × (3.74m/s)²) / 0.977m
T = (0.182kg × 13.9876m²/s²) / 0.977m
T = (2.5457432kgm²/s²) / 0.977m
T = 2.61kgm/s²
T = 2.61N
Therefore, the tension in the string when the ball is at the bottom of the path is 2.61 Newtons.
Learn more about Tension here: brainly.com/question/14351325
