Please name one type of wave that is not harmful:
2 answers:
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Answer:
Explanation:
Given
Airplane is flying with horizontally with a constant momentum during time interval
Impulse is given by change in momentum, so there is no net impulse on the Plane because momentum is constant
(b) As there is no change in momentum therefore impulse of thrust and air drag is balanced i.e. both are equal in magnitude but act in opposite direction
(a) The equilibrant C for force of vector A and B is 3.43 N.
(b) The equilibrant C for fx of vector A and B is 2.1 N.
(c) The equilibrant C, for fy of vector A and B is 2.12 N.
<h3>What is equilibrant force?</h3>An equilibrant force is a single force that will bring other bodies into equilibrium.
<h3>From configuration 1:</h3>Vector A: mass = 0.2 kg, θ = 20⁰
Vector B: mass = 0.15 kg, θ = 80⁰
Fx = mg cosθ
Fy = mg sinθ
where;
- m is mass
- g is acceleration due to gravity
Force of A due to its weight
F(A) = mg
F(A) = 0.2 x 9.8 = 1.96 N
Fx = (0.2 x 9.8) cos(20) = 1.84 N
Fy = (0.2 x 9.8) sin(20) = 0.67 N
<h3>Resultant force</h3>R = √(0.67² + 1.84²)
R = 1.96 N
<h3>Vector B</h3>Force of B due to its weight
F(B) = mg
F(B) = 0.15 x 9.8
F(B) = 1.47 N
Fx = (0.15 x 9.8) cos(80) = 0.26 N
Fy = (0.15 x 9.8) sin(80) = 1.45 N
<h3>Resultant force </h3>R = √(0.26² + 1.45²)
R= 1.47 N
<h3>Equilibrant C of vector A and B</h3>Equilibrant force:
Force, C = 1.96 N + 1.47 N
Force, C = 3.43 N
Equilibrant FX:
Fx, C = Fx(A) + Fx(B)
Fx, C = 1.84 N + 0.26 N = 2.1 N
Equilibrant FY:
Fy, C = Fy(A) + Fy(B)
Fy, C =0.67 N + 1.45 N = 2.12 N
Learn more about equilibrant force here: brainly.com/question/8045102
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