Answer:
minimum stopping distance will be d = 75 m
Explanation:
Maximum force exerted by the bracket is given as
F = 9000 N
now we know that mass of the object is
m = 6000 kg
so the maximum acceleration that truck can have is given as
now for finding minimum stopping distance of the truck
Work done by the car is 3900 J
Explanation:
- Power and work are related by the equation, Power = Work Done/Time
- Power is the rate at which work is done.
- Here, the car uses power of 260 W and time taken is 15 s.
Work Done = Power × Time
= 260 × 15 = 3900 J
Answer:
The distance traveled!
Explanation:
This is a velocity time graph of an object moving in a straight line due North.
Mass is the physical quantity
Answer:
1.64 * 10^(-5) m
Explanation:
Parameters given:
Angular separation, θ = 0.018 rad
Wavelength, λ = 589 nm = 5.89 * 10^(-7) m
The angular separation when there are 2 slots is given as
θ = λ/2d
where d = separation between slits
d = λ/2θ
d = (589 * 10^(-9))/(2 * 0.018)
d = 1.64 * 10^(-5) m
