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3 years ago

8

Driving a motor vehicle often requires __________ reaction time.

2 answers:

Anastasy [175]3 years ago

8 0

It often requires STANDARD reaction time

Ronch [10]3 years ago

6 0

Answer:

Driving a motor vehicle often requires <u>LESS or STANDARD</u> reaction time.

Explanation:

While driving on road it requires less or standard reaction time because while driving the motor vehicle on road the situation to make instant decision may occur at any time. While driving on road there may happen that the person driving in front of you may apply brakes instantly.

Due to this you have to instantly react for that situation and apply brakes in your car also.

If our reaction time is not standard or less then in that case the our car will travel closer to the car front of us and then if we even apply hard push on the brakes then also the car will not stop and it will skid towards the another car and it may occur collision with it.

So it always requires less or standard reaction time

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A car moves uphill at 40 km/h and then back downhill at 60 km/h. What is the average speed for the round trip?

jok3333 [9.3K]

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$S_a_v_e_r_a_g_e=48km/h$

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Ok, the average speed can be calculate with the next equation:

$S_a_v_e_r_a_g_e=\frac{Total\hspace{3}distance}{Total\hspace{3}time}$ (1)

Basically the car cover the same distance "d" two times, but at different speeds, so:

$Total\hspace{3}distance=2*d$

and the total time would be the time t1 required to go from A to B plus the time t2 required to go back from B to A:

$Total\hspace{3}time=t1+t2$

From basic physics we know:

$t=\frac{d}{S1}$

so:

$t1=\frac{d}{S1}$

$t2=\frac{d}{S2}$

Using the previous information in equation (1)

$S_a_v_e_r_a_g_e=\frac{2*d}{\frac{d}{S1} +\frac{d}{S2} }=\frac{2*d}{\frac{d*S2+d*S1}{S1+S2} }$

Factoring:

$S_a_v_e_r_a_g_e=\frac{2*S1*S2}{S1+S2}$ (2)

Finally, replacing the data in (2)

$S_a_v_e_r_a_g_e=\frac{2*40*60}{60+40} =48km/h$

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3 years ago

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gulaghasi [49]

Explanation:

i) center of gravity (or mass)

ii) m = W/g = (160 N)/(9.8 m/s^2)

= 16.3 kg

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3 years ago