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andriy [413]
4 years ago
9

Need help please!! I literally am dumb and can’t do this

Physics
1 answer:
natta225 [31]4 years ago
6 0

Answer:

The answer should be A and B. I don't fully know so don't quote me on that! Haha.

Explanation:

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Read through the scenarios below and calculate the predicted change in kinetic energy of the object compared to a 100 kg ball tr
sashaice [31]

Okay, first off, the formula for Kinetic Energy is:

<em>KE = 1/2(m)(v)^2</em>

<em>m = mass</em>

<em>v = velcoity (m/s)</em>


Using this formula, we can then calculate the kinetic energy in each scenario:

1) KE = 1/2(100)(5)^2 = 1,250 J

2) KE = 1/2(1000)(5)^2 = 12,500 J

3) KE = 1/2(10)(5)^2 = 125 J

4) KE = 1/2(100)(5)^2 = 1,250 J

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4 years ago
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A particle moving along the x-axis has its velocity described by the function vx =2t2m/s, where t is in s. Its initial position
Illusion [34]

Answer:

Follows are the solution to this question:

Explanation:

In point a:

Place of particles

X(t)=\int V_{x}(t)dt

       =\int 2t^{2}dt\\\\=\frac{2}{3}t^{3}+C

\to t=0\\\\ \to X(0)=2.3 \ m

\to X(0)=0+C\\\\ \to C=2.3\  m

\to X(t)=( \frac{2}{3})t^3 + 2.3\\\\ \to t=2.2\\\\\to X=( \frac{2}{3})\times 2.2^3 +2.3 \\\\

        = \frac{2}{3}\times 10.648 +2.3\\\\= \frac{21.296}{3}+2.3\\\\  = 7.09+2.3\\\\ =9.39\\\\ =9.4\ m

In point b:

when t=2.2 \ s

the Particle velocity  (V)=2 \times 2.22 =9.68\  \frac{m}{s}

In point c:

Calculating the Particle acceleration:

\to a=\frac{dV}{dt} =4\ t\\\\\to t=2.2 \ s\\\\\to a=4\times 2.2  =8.8 \ \frac{m}{s^2}

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Answer:

D

Explanation:

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Which object would have a LARGER gravitational force acting upon it? (assume the objects are at the same height above the Earth.
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It would be D because there is more gravitational forces acting on it than a small block of wood 
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