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4 years ago

Need help please!! I literally am dumb and can’t do this

Physics

1 answer:

natta225 [31]4 years ago

6 0

Answer:

The answer should be A and B. I don't fully know so don't quote me on that! Haha.

Explanation:

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4 years ago

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A firecracker sitting on the ground explodes into two pieces. Immediately after the explosion, one of the pieces has momentum of

Misha Larkins [42]

Answer:

other part will move with momentum 0.5 kg m/s towards west

Explanation:

As we know that the during the explosion event the time interval is very small and there is no impulsive force on the firecracker during this time

so here we can say that the momentum will remains conserved during the this event

now if the initial momentum of the firecracker is zero

then the final momentum must be zero

so here we can say

$P_1 + P_2 = 0$

$P_1 = 0.5 kg m/s$ towards east

now from above equation

$P_2 = - P_1 = -0.5 kg m/s$

so the other part will move with momentum 0.5 kg m/s towards west

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4 years ago

An airplane accelerates from a speed of 88m/s to a speed of 132 m/s during a 15 second time interval. How far did the airplane t

Gelneren [198K]

Answer:

$1650\:\mathrm{m}$

Explanation:

We can use the following kinematics equations to solve this problem:

$v_f=v_i+at,\\{v_f}^2={v_i}^2+2a\Delta x$ .

Using the first one to solve for acceleration:

$132=88+a(15),\\15a=44,\\a=\frac{44}{15}=2.9\bar{3}\:\mathrm{m/s^2}$ .

Now we can use the second equation to solve for the distance travelled by the airplane:

$132^2=88^2+2\cdot2.9\bar{3}\cdot \Delta x,\\\Delta x= \frac{9680}{2\cdot2.9\bar{3}},\\\Delta x =\fbox{$ 1650\:\mathrm{m}$}$ (three significant figures).

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