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Inga [223]
3 years ago
10

An egg is thrown horizontally off the top row bleachers at the Brickyard,

Physics
1 answer:
Ludmilka [50]3 years ago
6 0

Answer:

4

Explanation:

Divide 30 meters by 7.5 and you´re answer is 4. This is how I would think you solve the problem

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2. Sherlock Holmes established and ran the first ever crime laboratory.<br> True<br> False
alex41 [277]

Answer:

Explanation:

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3 years ago
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Stated that animals,as well as plants, are made of cells
koban [17]
Yes everything is made of cells because without cells our being can't stay together.
7 0
4 years ago
What are the potential out comes of force
AysviL [449]

Answer:

F in the definition of potential energy is the force exerted by the force field, e.g., gravity, spring force, etc. The potential energy U is equal to the work you must do against that force to move an object from the U=0 reference point to the position r.

Explanation:

5 0
2 years ago
A ball on the end of a string is revolving at a uniform rate in a vertical circle of radius 97.7 cm. If its speed is 3.74 m/s, a
noname [10]

The tension in the string when the ball is at the bottom of the path is 2.61 Newtons.

<h3>Tension</h3>

A tension is simply referred to as a force along the length of a flexible medium such as strings, cable, ropes etc.

Tension in a string revolving can be determined using the expression;

T = mv² / r

Where m is mass of object, v is velocity and r is radius ( length of string )

Given the data in the question;

  • Mass of ball m = 0.182kg
  • Radius ( length of string ) r = 97.7cm = 0.977m
  • Velocity = 3.74m/s
  • Tension in the string; T = ?

To determine tension in the string, we substitute our given values into the expression above.

T = mv² / r

T = (0.182kg × (3.74m/s)²) / 0.977m

T = (0.182kg × 13.9876m²/s²) / 0.977m

T = (2.5457432kgm²/s²) / 0.977m

T = 2.61kgm/s²

T = 2.61N

Therefore, the tension in the string when the ball is at the bottom of the path is 2.61 Newtons.

Learn more about Tension here: brainly.com/question/14351325

7 0
2 years ago
an ice skater starts with a velocity 2.25 m/s in a 50.0 degree direction after 8.33s she is moving 4.65 m/s in a 120 degree dire
svetoff [14.1K]

Answer:

-0.032 m/s^2

Explanation:

To answer the question, we just need to consider the motion along the horizontal direction.

The component of the initial velocity of the ice skater along the x-direction is:

u_x = u cos \theta =(2.25)(cos 50^{\circ})=1.45 m/s

where u = 2.25 m/s is the initial velocity and 50^{\circ} is the angle.

The component of the final velocity of the ice skater along the x-direction is

v_x = u cos \theta =(4.65)(cos 120^{\circ})=-2.33 m/s

where u = 4.65 m/s is the final velocity and 120^{\circ} is the angle.

The acceleration along the x-direction is given by

a_x=\frac{v_x-u_x}{t}

where

t = 120 s is the time

Substituting,

a=\frac{-2.33-(1.45)}{120}=-0.032 m/s^2

7 0
4 years ago
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