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julia-pushkina [17]
3 years ago
8

Cations are formed by _____. gaining protons losing protons gaining electrons losing electrons

Chemistry
2 answers:
Ede4ka [16]3 years ago
7 0
Cations are formed by losing electrons in the valence shell of atoms. There are more protons than electron ions making the atom more positive.
balandron [24]3 years ago
5 0

An anion has <em><u>gained electrons</u></em> and therefore has more electrons than protons. It has a negative charge.


An example if this doesn't make too much sense.

Charged Atoms: If electrons are removed from an atom, that atom becomes positively charged because it has more positive charge carriers (protons) than negative charge carriers (electrons)

These types of charged atoms are called positive ions or, cations. DEPENDING ON THE CIRCUMSTANCES, the removed electrons can remain free or they may attach themselves to another atom that can accept extra electrons. If this occurs, a negatively charged ion, or anion, is created.


I hope I made this clear enough for anyone who needed help on this. Hope this helps!!! Have a great day :)))

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Read the given equation. 2Na + 2H2O ? 2NaOH + H2 During a laboratory experiment, a certain quantity of sodium metal reacted with
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Answer:

The number of moles of Na metal that used initially = 0.70 mol.

The quantity of Na metal used initially to produce 7.80 of H₂ gas = 16.02 g.

Explanation:

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<em>2Na + 2H₂O → 2NaOH + H₂,</em>

  • The balanced equation shows that <em>2.0 moles of Na metal </em>react with 2.0 moles of water to produce 2.0 moles of NaOH and <em>1.0 mole of H₂</em>,
  • Firstly, we need to convert the volume of H₂ (7.80 L) produced to no. of moles (n) using the ideal gas law: <em>PV = nRT</em>,

where, P is the pressure of the gas in atm<em> (P at STP = 1.0 atm)</em>,

V is the volume of the gas in L <em>(V = 7.80 L)</em>,

n is the number of moles in mole,

R is the general gas constant<em> (R = 0.082 L.atm/mol)</em>,

T is the temperature of the gas in K <em>(T at STP = 0.0 °C + 273 = 273.0 K)</em>.

∴ The number of moles of H₂ gas (n) = PV / RT = [(1.0 atm)(7.80 L)] / [(0.082 L.atm/mol.K)(273.0 K)] = 0.35 mol.

<em>Using cross multiplication:</em>

2.0 moles of Na will produce → 1.0 mole of H₂, from the stichiometrey.

??? moles of Na will produce → 0.35 mole of H₂.

∴ The number of moles of Na metal that used initially = (2.0 mol)(0.35 mol) / (1.0 mol) = 0.70 mol.

Now, we can get the quantity of Na metal using the relation:

∴ mass = n x molar mass = (0.70 mol)(22.989 g/mol) = 16.02 g.

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