Answer:
Emprical formula = FeS206
Explanation:
Empirical formula is a formula that shows the ratio of elements present in a compound. Empirical formula does not give you the amount of the actual number of atom present in the compound but the proportion of the elements in the compound.
Calculating the empirical formula for a compound with 28% of iron, 24% of sulfur and 48% of oxygen by mass simply indicate the compound is 100% by mass. Or one could denote the percentage as mass(gram)
Usually
Molarity(mol) = mass/ molar mass
we look for the Molarity value to get the ratio of the elements present in the compound.
Fe(iron) = mass/molar mass = 28/55.845 = 0.50138776972 mol
S(sulfur) = mass /molar mass = 24 / 32.065 = 0.7484796507 mol
O2(oxygen) = mass/molar mass = 48 / 15.999 = 3.00018751172 mol
Divide through the mole value by the smallest mol number
0.50138776972/0.50138776972 = 1 mol iron
0.7484796507/ 0.50138776972 = 1.4928159319 ≈ 2 sulfur
3.00018751172/0.50138776972 = 5.98376684257 ≈ 6 oxygen
The value gotten is used as a subscript in the empirical formula.
Empirical formula = FeS206
