Answer:
horizontal velocity vh = 6*cos(30°) = 6*(√3)/2 = 3√3 m/s
initial vertical velocity vv = 6*sin(30°) = 6/2 = 3m/s
Using s = ut + at2/2 for change in vertical distance in time t, with acceleration a (-9.8m/s2) and initial velocity u (vv = 3m/s) we have
0 = 3*t - 9.8*t2/2 or t = 6/9.8 s (ignoring the t = 0 solution, which just represents staying still!).
The horizontal distance in time t is vh*t or 3√3*6/9.8 m
Explanation:
-- The two 8-ohm resistors in parallel are equivalent to
a single 4-ohm resistor.
-- The current in the circuit is
(voltage) / (resistance) = (9v) / (4ohms) = 2.25 Amperes
-- If another resistor is added in parallel, then no matter how large
or small it is, the current in the circuit increases.
(When another lane is added to a road, the traffic capacity of the
road increases.)
The circuit is now equivalent to a 12.5-ohm resistor in parallel
with 4-ohms. That's ...
(12.5 x 4) / (12.5 + 4) = 50/16.5 = 3.03 ohms .
-- The new current is (9v) / (3.03 ohms) = 2.97 Amperes
A redshift reveals how an object in space (star/planet/galaxy) is moving compared to us. It lets astronomers measure a distance for the most distant (and therefore oldest) objects in our universe
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