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Murrr4er [49]
4 years ago
9

estimate the force that a cyclist travelling at 6m/s needs to apply to the brakes to bring the bicycle to a stop in a distance o

f 15m. Ignore air resistance & friction.
Physics
1 answer:
RSB [31]4 years ago
4 0

v1 = 6m/s

v2 = 0

∆v = v1 - v2 = 6m\s

s = t * v = 15m

t = s\v1 = 15(m) \ 6(m\s) = 2.5s

a = ∆v\t = 6(m\s) \ 2.5s = 2.4m\s2

a = F\m = 2.4m\s2

F = a * m = 2.4m\s2 * ?kg

I can't tell you this because I don't know the mass of this cyclist

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In each case, three charged particles are fixed in place at the vertices of an equilateral triangle. The triangles are all the s
spayn [35]

Answer:

hello your question is incomplete attached below is the complete question

answer : F_{E} > F_{F} > F_{A} = F_{B}   > F_{C} =F_{D}

Explanation:

The explanation behind the reasoning is attached below

Ranking the magnitude of the net electric force on the lower-left particle from the greatest to the least

F_{E} > F_{F} > F_{A} = F_{B}   > F_{C} =F_{D}

5 0
3 years ago
A straight, nonconducting plastic wire 8.00 cm long carries a charge density of 100 nC/m distributed uniformly along its length.
Sphinxa [80]

Answer:

(A) 16641 N/C (B) 72000 N/C

Explanation:

We have given the length of the wire = 8 cm =0.08 m

Charge density = 100 nC/m

So charge = 100 ×0.08 = 8 nC =8\times 10^{-9}C

(A) Electric field E that produce 6 cm directly above its midpoint will be

E=\frac{KQ}{X\sqrt{X^2+a^2}}=\frac{9\times 10^9\times 8\times 10^{-9}}{0.06\sqrt{0.06^2+(\frac{0.08}{2})^2}}=16641N/C

Here X is the distance where we have to find the electric field

(B) Now electric field due to flat ring will be

E=\frac{KQX}{(X^2+a^2)^\frac{3}{2}}

Here X is the distance where we have to find the electric field

So E=\frac{9\times 10^9\times 8\times 10^{-9}}{(0.06^2+0.08^2)^\frac{3}{2}}=72000N/C

7 0
4 years ago
Two balloons are charged with an identical quantity and type of charge: -6.25 nanoCoulombs (10-9). They are held apart at a sepa
xenn [34]

Answer:

force between both the balloons is 9.23\times 10^{-7}N  

Explanation:

It is given charge on both balloons are same and equal to q=-6.25\times 10^{-9}C

Separation between both the balloons r=61.7cm=0.617m

According to Coulomb's law force between two charges is given by

F=\frac{1}{4\pi \epsilon _0}\frac{q^2}{r^2}=\frac{Kq^2}{r^2}

Therefore force is equal to

F=\frac{9\times 10^9\times (-6.25\times 10^{-9})^2}{0.617^2}

F=9.23\times 10^{-7}N

So force between both the balloons is 9.23\times 10^{-7}N

3 0
3 years ago
Two negative charges that are both -3.0 C push each other apart with a force of 19.2 N. How far apart are the two charges ?
fgiga [73]
The Coulomb's force acting between two charges is
F=k_e  \frac{q_1 q_2}{r^2}
where k_e = 8.99 \cdot 10^9 N m^{-2}C^{-2} is the Coulomb's constant, q1 and q2 the two charges, and r the distance between them.

Using q_1 = q_2 = -3 C, we can find the distance between the two charges when the force is F=19.2 N:
r=  \sqrt{k_e  \frac{q_1 q_2}{F} }=  \sqrt{ 8.99\cdot 10^9 \frac{(-3.0C)^2}{19.2 N} }=6.5 \cdot 10^4 m = 65 km
5 0
3 years ago
how do scientists know that black holes exist A. by running experiments on the sun B. by observing objects and light around blac
NNADVOKAT [17]

Answer:

E. none of the above

Explanation:

I hope thats right

8 0
3 years ago
Read 2 more answers
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