Ask question

Ask question

All categories

3 years ago

12

Complete the following radioactive decay problem. 238 Np → 93 0 e + - 1

1 answer:

JulijaS [17]3 years ago

5 0

Answer:

238 94Pu

Explanation:

From the question given, we noticed that the element is undergoing beta minus decay. This means that the daughter nuclei obtained will have the same mass number as the parent element and the the atomic number of the daughter nuclei will increase by 1.

Please see attached photo on how to arrive at the answer.

You might be interested in

Last one i think.......

MatroZZZ [7]

Answer is c i believe

4 0

3 years ago

Read 2 more answers

Find the independent variable and the dependent variable :)))

Naddik [55]

Answer:

dependent variable: plant growth

independent: sunlight impact/amount of light

Explanation:

6 0

3 years ago

What is the concentration of ammonium ions in a 0.100 M solution of (NH3)2SO4?

adelina 88 [10]

<span>ammonium sulphate give 2 moles of ammonium ions
so conc. of ammonium ions =2*0.100=0.200 </span>

3 0

3 years ago

Which of the following is a binary compound?

MrRa [10]

Answer: A. CaO

Took the test already.

3 0

3 years ago

Read 2 more answers

The volume of a carbon atom is 1.9 x 10–30 m3. What is the radius of the atom in picometers? The volume of a sphere is (4/3)(pi)

skelet666 [1.2K]

Volume of sphere = $\frac{4}{3}\pi r^{3}$

where, $\pi$ = $3.14$

r = radius of sphere

Put the given value of volume in above formula i.e. ( $1.9\times 10^{-30}m^{3}$ )

Thus,

$1.9\times 10^{-30}m^{3} = \frac{4}{3}\3.14 r^{3}$

$1.9\times 10^{-30}m^{3} = 4.1867 r^{3}$

$r^{3} = \frac{1.9\times 10^{-30}m^{3}}{4.1867}$

$r^{3} = 0.453\times 10^{-30}m^{3}$

$r = \sqrt[3]{0.453\times 10^{-30}m^{3}}$

= $0.768\times 10^{-10}m$

= $7.68\times 10^{-12}m$

= $7.68 picometers$

Thus, radius of the carbon atom is $7.68 picometers$

6 0

3 years ago

Read 2 more answers