<h3>
Answer:</h3>
12.387 moles
<h3>
Explanation:</h3>
We are given;
Temperature of chlorine, T = 120°C
But, K = °C + 273.15
Therefore, T = 393.15 K
Pressure, P = 33.3 Atm
Volume, V = 12 L
We are required to calculate the number of moles of chlorine gas,
To find the number of moles we are going to use the ideal gas equation;
PV = nRT
R is the ideal gas constant, 0.082057 L.atm/mol.K
Therefore, rearranging the formula;
n = PV÷RT
Hence;
n = (33.3 atm × 12 L) ÷ (0.082057 × 393.15 K)
= 12.387 moles
Therefore, the number of moles of chlorine are 12.387 moles
Answer:
78.85
Explanation:
To <u>calculate the average atomic mass of the isotopes </u>we use the <em>given masses and abundances</em>, as follows:
- Mass of Isotope 1 * Abundance of Isotope 1 + Mass of Isotope 2 * Abundance of Isotope 2 + ....
In other words:
- 78 amu * 75/100 + 81 amu * 15/100 + 82 amu * 10/100 = 78.85
So the answer is 78.85.
B is the answer
I double checked hope it helps
Answer:
1.80 x 10^24 atoms
Explanation:
3moles × 6.022×10^23 atoms/mole
