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garri49 [273]
3 years ago
15

Identify two physical properties and two chemical properties of a bag of microwave popcorn before popping and after

Chemistry
2 answers:
krek1111 [17]3 years ago
4 0
Physical properties of a bag of microwaveable popcorn are the mass of it, the color of it, the size of it, and the weight of it. Two chemical properties of a bag of microwavable popcorn are it changed from seeds to popcorn and it popped.
noname [10]3 years ago
3 0

Answer: The correct answer is:

- Before :

Physical: almost flat & cool to the touch

Chemical: flammability & change from kernels to fluffy popcorn

- After :

Physical: hot & increased volume

Chemical: inability of popcorn to change back into uncooked kernels & flammability

Explanation:

Physical properties are those that can be measured without affecting the composition or identity of the substance. Examples of these properties are density, melting point, boiling point, among others.

There are also chemical properties, which are observed when a substance undergoes a chemical change, that is, a transformation of its internal structure, becoming other new substances. These chemical changes can be reversible or irreversible, when the latter occur in only one direction (as in the combustion of wood).

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Explanation:

Formula to calculate radius is as follows.

          p(r) = Ar(r^{2}e^{\frac{-r}{3a_{o}}}

                = Ar^{3}e^{\frac{-r}{3a_{o}}}

     \frac{dp(r)}{dr} = 0

            Ar^{3}e^{\frac{-r}{3a_{o}}}(\frac{-1}{3a_{o}} + Ae^{\frac{-r}{3a_{o}}}(3r^{2}) = 0

                     \frac{Ar^{3}}{3a_{o}}e^{\frac{-r}{3a_{o}}}

                      = 3Ar^{2}e^{\frac{-r}{3a_{o}}}

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Thus, we can conclude that most likely radius at which the electron would be found is 9a_{o}.

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3 years ago
25. Which is not a form of chemical changer
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C. Digestion is the answer.

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Question a chemist mixes 35 milliliters of a solution that is 18% acid with 90 milliliters of a solution that is 68% acid. answe
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Missing questions: 
<span>a) How many milliliters of acid are in the resulting mixture?
b) What percentage of the resulting mixture is acid?
a) V</span>₁ = 35 ml.
ω₁ = 18% = 0,18.
V₂ = 90 ml.
ω₂ = 68% = 0,68.
V(acid) = V₁ · ω₁ + V₂ · ω₂.
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