That statement is <em>false</em>.
"Condense" is what a gas does when it turns into liquid, and that's something that happens when the gas is cooled, not heated.
Answer:
M = I A definition of magnetic moment - current * area
A = π R^2 = π * (6.4E6)^2 = 1.3E14 m^2
I = 8E22 A-m^2 / 1.3E14 m^2 = 6.2E8 amperes
I = 620,000,000 amps
Answer:
0.739
Explanation:
If we treat the four tire as single body then
W ( weight of the tyre ) = mass × acceleration due to gravity (g)
the body has a tangential acceleration = dv/dt = 5.22 m/s², also the body has centripetal acceleration to the center = v² / r
where v is speed 25.6 m/s and r is the radius of the circle
centripetal acceleration = (25.6 m/s)² / 130 = 5.041 m/s²
net acceleration of the body = √ (tangential acceleration² + centripetal acceleration²) = √ (5.22² + 5.041²) = 7.2567 m/s²
coefficient of static friction between the tires and the road = frictional force / force of normal
frictional force = m × net acceleration / m×g
where force of normal = weight of the body in opposite direction
coefficient of static friction = (7.2567 × m) / (9.81 × m)
coefficient of static friction = 0.739
Answer:
The apparent weight is 5 times greater than the original weight at the bottom.
Explanation:
Given:
Mass of the pilot, m = 84 kg
Velocity of the jet, v = 345 m/s
Radius of the loop, R = 3.033 km = 3.033 * 10^3 m
We have to find the apparent weight that the pilot feels.
Let the apparent weight be "N" .
Apparent weight :
- It is based on where is the position of the pilot in the loop-the-loop.
- The apparent weight is the highest at the bottom of the loop-the-loop.
- Because the weight acts down and the normal force acts towards the center of the circle.
From the FBD shown we can say that :
apparent weight (N)
⇒ 
⇒ 
⇒ 
⇒ 
Therefore,
The force exerted by the seat on the pilot at the bottom of the loop is greater than the pilots weight by a factor of 5.
