1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Misha Larkins [42]
3 years ago
12

At a certain time a particle had a speed of 18 m/s in the positive x direction, and 2.4 s later its speed was 30 m/s in the oppo

site direction. What is the average acceleration of the particle during this 2.4 s interval?
Physics
1 answer:
hoa [83]3 years ago
3 0
<h2>Average acceleration of the particle during the 2.4 s interval is -20 m/s²</h2>

Explanation:

We have equation of motion v = u + at

     Initial velocity, u =  18 m/s

     Final velocity, v =  -30 m/s    

     Time, t = 2.4 s

     Substituting

                      v = u + at  

                      -30 = 18 + a x 2.4

                      a = -20 m/s²

     Acceleration is -20 m/s²

Average acceleration of the particle during the 2.4 s interval is -20 m/s²

You might be interested in
Alright eksqijakojqnlqozjzbw.wlisj
saw5 [17]

Answer:

eksqijakojqnozjzbw.wlisjaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa

Explanation:

6 0
3 years ago
A person must pull a rope 20 meters with a force of 200 N what is the work input?
tatiyna
Work done = force * distance
work done = 200 * 20
work done = 4000J
4 0
3 years ago
The apparent weight of a student in alift is 564N . if the mass of the student is 60.3kg, what is the acceleration of the lift ?
Yuki888 [10]

Answer:

-.457 m/s^2

Explanation:

Actual weight =   60 .3 (9.81) = 591.54 N

Accel of lift changes this to    60.3 ( 9.81 - L)     where L - accel of lift

                                           60.3 ( 9.81 - L ) = 564

                                               solve for L = .457 m/s^2  DOWNWARD

                                                        so L = - .457 m/s^2

4 0
2 years ago
Torque can cause the angular momentum vector to rotate in UCM. This motion is called ___________.
emmainna [20.7K]

Torque can cause the angular momentum vector to rotate in UCM. This motion is called _Conservation of Angular momentum__________.

Answer:

Conservation of Angular momentum

Explanation:

The motion of an object in a circular path at constant speed is known as uniform circular motion (UCM). An object in UCM is constantly changing direction, and since velocity is a vector and has direction, you could say that an object undergoing UCM has a constantly changing velocity, even if its speed remains constant.

The law of conservation of angular momentum states that when no external torque acts on an object, no change of angular momentum will occur.

Key Points

When an object is spinning in a closed system and no external torques are applied to it, it will have no change in angular momentum.

The conservation of angular momentum explains the angular acceleration of an ice skater as she brings her arms and legs close to the vertical axis of rotation.

If the net torque is zero, then angular momentum is constant or conserved.

Angular Momentum

The conserved quantity we are investigating is called angular momentum. The symbol for angular momentum is the letter L. Just as linear momentum is conserved when there is no net external forces, angular momentum is constant or conserved when the net torque is zero. We can see this by considering Newton’s 2nd law for rotational motion:

τ→=dL→dt, where  

τ is the torque. For the situation in which the net torque is zero,  

dL→dt=0.

If the change in angular momentum ΔL is zero, then the angular momentum is constant; therefore,

⇒

L  =constant

L=constant (when net τ=0).

This is an expression for the law of conservation of angular momentum.

Example and Implications

An example of conservation of angular momentum is seen in an ice skater executing a spin,  The net torque on her is very close to zero,

because (1) there is relatively little friction between her skates and the ice, and (2) the friction is exerted very close to the pivot point.

Conservation of angular momentum is one of the key conservation laws in physics, along with the conservation laws for energy and (linear) momentum. These laws are applicable even in microscopic domains where quantum mechanics governs; they exist due to inherent symmetries present in nature.

7 0
3 years ago
Which illustration represents low accuracy but high precision?​
Misha Larkins [42]

Answer:

D i think

Explanation:

7 0
3 years ago
Read 2 more answers
Other questions:
  • In my trigonometry class, we were assigned a problem on Angular and Linear Velocity.
    5·1 answer
  • What is the difference between methane and fluorinated gases
    15·1 answer
  • A pillow with mass of 0.3 kg sits on a bed with a coefficient of static friction of 0.6. What is the maximum force of static fri
    6·2 answers
  • A source emits sound uniformly in all directions. There are no reflections of the sound. At a distance of 12 m from the source,
    15·1 answer
  • Sarah launches her purse straight up in air with a velocity of 30.2m/s<br> How high will it go?
    14·1 answer
  • Please explain what is couloms law?
    10·1 answer
  • Im confused on how to do this
    9·1 answer
  • Can someone please help me​
    14·1 answer
  • A rock with a mass of 80grams dropped into a graduated cylinder with 30 ml of water in it the readingof water became 70 ml what
    14·1 answer
  • A student pushes on a 8-kg box with a force of 35 N forward. The force of sliding friction is 10 N backward. What is the acceler
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!