Answer:
(a) Silver, H = 455.67 J
(b) Iron, H = 870.67 J
(c) titanium, H = 1012.23 J
Explanation:
mass of block, m = 2.66 kg = 266 g
T1 = 25.87° C
T2 = 33.16° C
ΔT = T2 - T1 = 33.16 - 25.87 = 7.29° C
(a) Specific heat of silver, c = 0.235 J/g K
The heat required is given by
H = m x c x ΔT
H = 266 x 0.235 x 7.29 = 455.67 J
(b) Specific heat of iron, c = 0.449 J/g K
The heat required is given by
H = m x c x ΔT
H = 266 x 0.449 x 7.29 = 870.67 J
(c) Specific heat of titanium, c = 0.522 J/g K
The heat required is given by
H = m x c x ΔT
H = 266 x 0.522 x 7.29 = 1012.23 J
