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natulia [17]
3 years ago
8

What volume will be occupied by 5.00 mol of a gas at 25°C and 0.500 atm pressure?"

Chemistry
1 answer:
fomenos3 years ago
4 0

Answer:

The volume will be occupied is 244, 36L.

Explanation:

We convert the unit of temperature to celsius into Kelvin, then use the ideal gas formula, solve for V (volume) and use the gas constant R =0.082 l atm / K mol:

0°C=273K  25°C= 273 + 25=298K

PV=nRT ---> V=nRT/P

V= 5,00 mol x 0,082 l atm/ K mol x 298 K/0,500 atm

<em>V=244,36L</em>

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Period

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On the periodic table the numbers 1,2 and 3 can represent either groups or periods.

The periodic table gives the arrangement of elements based on their atomic numbers

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  • The vertical columns are made up of elements having the same number of electrons in their outermost shell.
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The distance between the peaks of wave is called​
larisa [96]

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3 years ago
A 0.2722 g sample of a pure carbonate, X n CO 3 ( s ) , was dissolved in 50.0 mL of 0.1200 M HCl ( aq ) . The excess HCl ( aq )
Alex73 [517]

Answer:

0.00369 moles of HCl react with carbonate.

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Number of moles of HCl present initially = \frac{0.1200}{1000}\times 50.0 moles = 0.00600 moles

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According to above equation, 1 mol of NaOH reacts with 1 mol of 1 mol of HCl.

So, excess number of moles of HCl present = number of NaOH added for back titration = \frac{0.0980}{1000}\times 23.60 moles = 0.00231 moles

So, mole of HCl reacts with carbonate = (Number of moles of HCl present initially) - (excess number of moles of HCl present) = (0.00600 - 0.00231) moles = 0.00369 moles

Hence, 0.00369 moles of HCl react with carbonate.

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The water in the leaf will evaporate

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