Based on your question the answer to this is the following and i hope i answered you question correctly:
How much energy is transferred to her eardrums each second ?
-6.31
<span>
How fast would a 2.00 mg mosquito have to fly to have this much kinetic energy? </span>
-1.39*10^-5<span>
How fast a typical 2.0 mg mosquito would have to fly (in mm/s) to have an amount of energy delivered to the eardrum each second when someone whispers (20 dB) a secret in your ear?
-</span><span>3.5 joules</span>
It is a privilege, because not everyone might have resources for training, and therefore no driving skills.
Answer:
4.04 s
Explanation:
h = vi + 1/2 a t ^2
HERE h = 80 m , vi = 0 , a =9.81 m/s^2
80 = 0 + 1/2 × 9.81 × t ^2
80 = 4.905 t^2
t^2 = 80/4.905
t ^2 = 16.30988
t = square root of 16.30988
t = 4.0385 s
t = 4.04 s
Answer:
[H3O+] = 0.00520 M
Explanation:
The dissociation of acetic acid in water is given by the equation;
CH3COOH + H2O<-------> H3O+ + CH3COO-
ka = [H+][C2H3O2-]/[HC2H3O2]
Ka = 1.8 x 10^-5
= x^2 / 0.150-x
x = [H3O+]= 0.00520 M
<span>Whatever the focus of the experiment is, plus any others factors that might influence the outcome of the experiment. If you are testing a new cancer drug, the experimental group and the control group must both be people with the same type of cancer, and both be a representative distribution of the population, all races, genders, ages, etc. You want the only difference in the two groups to be what you are studying, i.e. the effects of the drug.</span>
