False beacause that was one of the first things they thought
<span>Answer
is: mass of burned butane is 11.6 g.</span>
Chemical reaction: 2C₄H₁₀ + 13O₂ → 8CO₂ + 10H₂O.
m(butane)
= 50,0 g.
<span>
V(CO</span>₂) = 17,9 L.<span>
n(CO</span>₂) = V(CO₂) ÷
Vm.<span>
n(CO</span>₂) = 17,9 L ÷ 22,4 L/mol.<span>
n(CO</span>₂) = 0,8 mol.<span>
From chemical reaction n(CO</span>₂) :
n(C₄H₁₀) = 8 : 2.<span>
n(C</span>₄H₁₀) =
0,8 mol ÷ 4.<span>
n(C</span>₄H₁₀) =
0,2 mol.<span>
m(C</span>₄H₁₀) =
n(C₄H₁₀) · M(C₄H₁₀).<span>
m(C</span>₄H₁₀) =
0,2 mol · 58 g/mol.<span>
m(C</span>₄H₁₀) =
11,6 g.
Answer:
Molality = 0.43 m
Explanation:
Given data:
Mass of barium sulfide = 25.4 g
Mass of water = 349 g (349 g/1000 = 0.349 Kg)
Molality of water = ?
Solution:
Number of moles of barium sulfide:
Number of moles = mass/molar mass
Number of moles = 25.4 g/169.39 g/mol
Number of moles = 0.15 mol
Molality:
Molality = number of moles o f solute/ Kg of solvent
Molality = 0.15 mol / 0.349 Kg
Molality = 0.43 m
