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egoroff_w [7]
3 years ago
6

What is the acceleration of a 55 kg block of cement when pulled sideways with a net force of 356 N? Answer in units of m/s2.

Physics
1 answer:
puteri [66]3 years ago
5 0
F=ma
a=F/m = 356/55 = .... m/s2
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The answer is point b because vertical velocity is zero at the maximum height
8 0
3 years ago
Exercício:
zysi [14]

Answer:

a

Explanation:

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a is the answer

7 0
3 years ago
Una partícula se mueve en el plano XY efectúa un desplazamiento mientras actúa sobre ella una fuerza constante. X= (4i + 3j) m,
dsp73

Answer:

a) La magnitud del desplazamiento es de 5 m

La magnitud de la fuerza es 20 N

b) El trabajo realizado por la fuerza es de 100 J

c) El ángulo entre la fuerza y el plano es 0 °

Explanation:

a) La magnitud del desplazamiento se encuentra por la relación;

\left | X \right | = \sqrt{X_{x}^{2}+X_{y}^{2}}

Lo que da;

\left | X \right | = \sqrt{4^{2}+3^{2}} = 5 \ m

De manera similar, la magnitud de la fuerza, F, se encuentra como sigue;

\left | F \right | = \sqrt{F_{x}^{2}+F_{y}^{2}}

Lo que da;

\left | F \right | = \sqrt{16^{2}+12^{2}} = 20 \ N

b) El trabajo, W, realizado por la fuerza = Fuerza, F × Distancia, X

∴ Ancho = 20 N × 5 m = 100 N · m = 100 J

c) La dirección de la fuerza viene dada por la siguiente fórmula;

tan^{-1} \left (\dfrac{F_y}{F_x} \right ) = tan^{-1} \left (\dfrac{12}{16} \right )  = 38.9^{\circ}

La dirección del plano viene dada por la siguiente fórmula;

tan^{-1} \left (\dfrac{X_y}{X_x} \right ) = tan^{-1} \left (\dfrac{3}{4} \right )  = 38.9^{\circ}

Por tanto, el ángulo entre la fuerza y el plano = 0 °

La fuerza actúa a lo largo del plano.

6 0
3 years ago
A river flows due east at 12 km/h. A boat crosses the 720 m wide river by maintaining a constant velocity of 72 mi/h due north r
zhenek [66]

Answer:

The boat will be 74 .17 meters downstream by the time it reaches the shore.

Explanation:

Consider the vector diagrams for velocity and distance shown below.

converting 72 miles per hour to km/hr

we have 72 miles per hour 72 × 1.60934 = 115.83 km/hr

The velocity vectors form a right angled triangle, and can be solved using simple trigonometric laws

tan \theta = \frac{12}{115.873}

\theta = tan^{-1}(  \frac{12}{115.873})=5.9126

This is the vector angle with which the ship drifts away with respect to its northward direction.

<em>From the sketch of the displacement vectors,  we can use trigonometric ratios to determine the distance the boat moves downstream.</em>

Let x be the distance  the boat moves downstream.d

sin(5.9126)=\frac{x}{720}

x= 720\times 5.9126

x=74.17m

∴The boat will be 74 .17 meters downstream by the time it reaches the shore.

6 0
3 years ago
A car has a mass of 8000 kg and a kinetic energy of 24,000 J. What is its<br> speed?
Liula [17]

Answer:

30 mph

Explanation:

8 0
2 years ago
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