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Snowcat [4.5K]
2 years ago
5

Maria throws two stones from the top edge of a building with a speed of 20 m/s. She throws one straight down and the other strai

ght up. The first one hits the street in a time t1. How much later is it before the second stone hits
Physics
1 answer:
Georgia [21]2 years ago
7 0

Maria throws two stones from the top edge of a building at a speed of 20 m/s, The time is mathematically given as

t=4.5 sec.

<h3>How much later is it before the second stone hits?</h3>

Generally, the equation for speed  is mathematically given as

V = u+at

Therefore

0 = 22-9.8xt.

t = 22 /9.8 sec

t = 2.24489.

The same time will be taken from max^m height to point O

The extra time is taken

t=4.49 sec.

t=4.5 sec.

Read more about Time

brainly.com/question/4931057

#SPJ1

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Answer:

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v_{o} - Velocidad inicial, en metros por segundo.

v - Velocidad final, en metros por segundo.

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t - Tiempo, en segundos.

Si sabemos que v_{o} = -75\,\frac{m}{s}, g = -9.807\,\frac{m}{s^{2}} y t = 26\,s, entonces la velocidad final del mango es:

v = v_{o}+g\cdot t

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Answer:

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