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4 years ago

6

What does Newton's third law describe?

2 answers:

Lelechka [254]4 years ago

4 0

Answer:

Newton's Third law of motion: "Every action has an equal and opposite reaction."

Explanation:

An example of Newton's third law is when a rocket is launched, the boosters apply force on the ground and the ground pushes back, which makes the rocket take off.

Vesnalui [34]4 years ago

3 0

Answer:

Newton's third law is: For every action, there is an equal and opposite reaction.

Explanation:

The statement means that in every interaction, there is a pair of forces acting on the two interacting objects. The size of the forces on the first object equals the size of the force on the second object.

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Henri Becquerel is credited with the discovery of:

Yuri [45]

Radium........ Hope this helps :)

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3 years ago

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The coefficient of performance of a residential heat pump is 1.6. Calculate the heating effect in kJ/s this heat pump will produ

Andre45 [30]

Answer:

$Q_{H}=6.4kJ/s$

Explanation:

Given data

Coefficient of performance of a residential heat pump=1.6

Electrical power P=4kW

Required

Heat Q

Solution

The rate of heat produced is given as

$Q_{H}=COP_{HP}Win\\$

Substitute the given values

So

$Q_{H}=4kW*1.6\\Q_{H}=6.4kJ/s$

6 0

3 years ago

Find the range of projectile launched at the angle of 45 with an intial velocity of 25 m/s

Mekhanik [1.2K]

Answer:

10

Explanation:

Given that :

Initial Velocity (u) = 25 m/s

Range can be obtained using the relation :

Range = (u² * sin2θ) / g

g = 10m/s ; θ = 45

Range = [10² * sin2(45)] / 10

Range = [100 * 1] ÷ 10

Range = 10

5 0

3 years ago

E Which of the following particles that may be emitted in radioactive decay is not ionising?

mestny [16]

Explanation:

C. neutron.

it does not contain ionizing characteristics.

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5 0

3 years ago

The acceleration of an object (in m/s2) is given by the function a ( t ) = 6 sin ( t ) a(t)=6sin(t). The initial velocity of the

levacccp [35]

Answer:

$v(t)=-6cos(t)+4$

Explanation:

We have acceleration given by

$a(t)=6sin(t)$

Velocity at t = 0

$v(0)=-2\ m/s$

Velocity is given by

$v(t)=\int a(t)dt\\\Rightarrow v(t)=\int 6sin(t)dt\\\Rightarrow v(t)=6\int sin(t)\\\Rightarrow v(t)=-6cost+C$

at t = 0

$-2=-6cos0+C\\\Rightarrow -2+6=C\\\Rightarrow C=4$

The equation will be

$\mathbf{v(t)=-6cos(t)+4}$

8 0

3 years ago

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