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2 years ago

A force of 20 N acts upon a 5 kg block. What is the acceleration of the object.

Physics

2 answers:

horsena [70]2 years ago

7 0

Answer:

4m/s/s

Explanation:

a=f/m

m=5kg

f=20N

20/5=4

(N=kg-m/s/s)

ss7ja [257]2 years ago

3 0

A :-) F = ma
a = F by m
Given - F = 20 N
m = 5 kg
Solution -
a = F by m
a = 20 by 5
( cut 5 and 20 because 5 x 4 = 20 )
a = 4 m/s^2

.:. The acceleration is 4m/s^2.

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Lana71 [14]

Answer:

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Kinetic Force of Friction = 281.75 N

Explanation:

The static force of friction is equal to Coefficient of static Friction * Mass * g

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3 years ago

If a person weighs 818 N on earth and 5320 N on the surface of a nearby planet, what is the acceleration due to gravity on that

alexandr402 [8]

Answer:

$g'=63.74\ m/s^2$

Explanation:

It is given that,

Weight of the person on Earth, W = 818 N

Weight of a person is given by the following formula as :

$W=mg$

g is the acceleration due to gravity on earth

$m=\dfrac{W}{g}$

$m=\dfrac{818\ N}{9.8\ m/s^2}$

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The mass of an object is same everywhere. It does not depend on the location.

Let W' is the weight of the person on the surface of a nearby planet, W' = 5320 N

g' is the acceleration due to gravity on that planet. So,

$g'=\dfrac{W'}{m}$

$g'=\dfrac{5320\ N}{83.46\ kg}$

$g'=63.74\ m/s^2$

So, the acceleration due to gravity on that planet is $63.74\ m/s^2$ . Hence, this is the required solution.

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3 years ago