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alexira [117]
3 years ago
9

What is the difference between free fall and weightlessness

Physics
2 answers:
amid [387]3 years ago
6 0
Freefall can only be experienced when gravity is the only force acting on you. Weightlessness can be experienced on earth with air resistance and gravity like on a rollercoaster when you are just about to go down the hill.
TiliK225 [7]3 years ago
3 0
Free fall means your falling because of gravity and weight and will eventually hit the ground without any protection. weightlessness means a place or time where there is no gravity and you're floating and not falling.
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An ideal spring with spring constant k is hung from the ceiling. The initial length of the spring, with nothing attached to the
hram777 [196]

The mass m of the object = 5.25 kg

<h3>Further explanation</h3>

Given

k = spring constant = 3.5 N/cm

Δx= 30 cm - 15 cm = 15 cm

Required

the mass m

Solution

F=m.g

Hooke's Law

F = k.Δx

\tt m.g=k.\Delta x\\\\m.10=3.5\times 15\\\\m=5.25~kg

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2 years ago
How is work calculated when the force applied is not parallel to the displacement
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3 years ago
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Which of the following forms matter?<br> A. Proteins<br> B.atoms<br> C.cells<br> D. DNA
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Answer:b) atoms

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2 years ago
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How many number of musicians constitute a big band?
nikitadnepr [17]
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6 0
3 years ago
The 4kg head of a sledge hammer is moving at 6m/s when it strikes a chisel, driving it into a log. The duration of the impact (o
LUCKY_DIMON [66]

Answer:

The average impact force is 12000 newtons.

Explanation:

By Impact Theorem we know that impact done by the sledge hammer on the chisel is equal to the change in the linear momentum of the former. The mathematical model that represents the situation is now described:

\bar F \cdot \Delta t = m \cdot  (v_{2}-v_{1}) (1)

Where:

\bar F - Average impact force, in newtons.

\Delta t - Duration of the impact, in seconds.

m - Mass of the sledge hammer, in kilograms.

v_{1}, v_{2} - Initial and final velocity, in meters per second.

If we know that \Delta t = 0.0020\,s, m = 4\,kg, v_{1} = -6\,\frac{m}{s} and v_{2} = 0\,\frac{m}{s}, then we estimate the average impact force is:

\bar F = \frac{m\cdot  (v_{2}-v_{1})}{\Delta t}

\bar F = 12000\,N

The average impact force is 12000 newtons.

5 0
2 years ago
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