Which property of light is not explained by the wave model of light?

A jet plane flying 600 m/s experiences an acceleration of 4.0 g when pulling out of the circular section of a dive. What is the

Brilliant_brown [7]

To solve this problem we will apply the concepts related to the equations of linear motion and angular motion in order to find the radius. Our values are given as,

$g=9.81m/s^2$

Then

$4g= 39.24 m/s^2$

The relation between the acceleration and the angular velocity and the radius is,

$a_c=\omega^2*r$

The angular velocity and the lineal velocity can be related as,

$v=\omega r$

The acceleration and the velocity was given, then

$39.24=\omega^2 r$

$600=\omega r$ $\rightarrow r = \frac{600}{\omega}$

Replacing at the first equation we have,

$39.24 = \omega^2 (\frac{600}{\omega} )$

$\omega = \frac{39.24}{600}$

$\omega = 0.0654rad/s$

Now using this expression to find the radius we have that

$r = \frac{600}{\omega}$

$r = \frac{600}{0.0654}$

$r = 9174.31 \approx 9200m$

Therefore the correct answer is C.

5 0

3 years ago

Determine the specific heat of a certain metal if a 450 gram sample of it loses 34 500 Joules of heat as its temperature starts

slamgirl [31]

Answer:

c = 0.4356 J/gK

Explanation:

Given the following data;

Mass = 450 grams

Initial temperature, T1 = 150°C

Final temperature, T2 = 53°C

Quantity of heat = 34500 Joules

To find the specific heat capacity of the metal;

Heat capacity is given by the formula;

$Q = mcdt$

Where;

Q represents the heat capacity or quantity of heat.

m represents the mass of an object.

c represents the specific heat capacity of water.

dt represents the change in temperature.

dt = T2 - T1

dt = 53 - 150

dt = -97°C

Converting the temperature in Celsius to Kelvin, we have;

dt = 273 + (-97) = 176 Kelvin

Making c the subject of formula, we have;

$c = \frac {Q}{mdt}$

Substituting into the equation, we have;

$c = \frac {34500}{450*176}$

$c = \frac {34500}{79200}$

c = 0.4356 J/gK

6 0

3 years ago

A 190 g air-track glider is attached to a spring. The glider is pushed in 9.20 cm and released. A student with a stopwatch finds

Sholpan [36]

Answer:

$k = 12.136\,\frac{N}{m}$

Explanation:

The angular frequency of the system is:

$\omega = \sqrt{\frac{k}{m} }$

The frequency is:

$f = \frac{14\,osc}{11\,s}$

$f = 1.272\,hz$

The angular frequency is:

$\omega = 2\pi\cdot (1.272\,hz)$

$\omega = 7.992\,\frac{rad}{s}$

The spring constant is:

$k = \left(7.992\,\frac{rad}{s} \right)^{2}\cdot (0.190\,kg)$

$k = 12.136\,\frac{N}{m}$

6 0

3 years ago

A new system of units is invented where the basic unit of length is the "dak." The "dak" is defined as equal to 3 inches, and th

Goryan [66]

Answer:

1 cm = 0.131 daks

Explanation:

It is given that,

1 dak = 3 inches

and

1 inch = 2.54 cm

We need to find how many "daks" are there in a centimeter. We can do the conversions as follows :

$1\ dak=1\ dak\times \dfrac{3\ inches}{1\ dak}\times \dfrac{2.54\ cm}{1\ inch}$

$1\ dak=7.62\ cm$

$1\ cm=\dfrac{1}{7.62}\ dak$

1 cm = 0.131 dak

So, there are 0.131 daks in 1 centimeter. Hence, this is the required solution.

5 0

4 years ago

A 36,287 kg truck has a momentum of 907,175 kg • . What is the truck’s velocity?

Snowcat [4.5K]

By definition,
Momentum = Mass * Velocity

Let v = the velocity of the truck, m/s
The mass of the truck is 36,287 kg.
The momentum is 907,175 (kg-m)/s.

Therefore
907,175 (kg-m)/s = (36287 kg)*(v m/s)
v = 907175/36287 = 25 m/s

Answer: 25 m/s

7 0

4 years ago

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