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k0ka [10]
4 years ago
7

Holden is trying to determine the velocity of his race car. He went 20 meters east, turned around, and went 40 meters west. He t

urned the car one more time and went 35 meters east. His car was 15 meters from the starting line. This took 5 seconds.
What is the car’s velocity?
A. 3 m/s west

B.3 m/s east

C. 19 m/s west

D. 19 m/s east
Physics
2 answers:
Volgvan4 years ago
6 0
Although the car's average speed is  19 m/s ,
its velocity is  3 m/s east.

Velocity is        (displacement) / (time)

and Displacement is the distance between the start point and
end point, no matter what route was traveled between them. 

In this case, the displacement is 15 meters east.
So the velocity is

               (15 meters east) / (5 sec) = 3 meters/sec east .
kupik [55]4 years ago
3 0

Although the car's average speed is  19 m/s ,

its velocity is  3 m/s east.

Velocity is        (displacement) / (time)

and Displacement is the distance between the start point and

end point, no matter what route was traveled between them. 

In this case, the displacement is 15 meters east.

So the velocity is

          Answer:    (15 meters east) / (5 sec) = 3 meters/sec east .

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Artist 52 [7]

\huge{ \mathfrak{  \underline{ Answer} \:  \:  ✓ }}

1. Calculate the equivalent resistance in the circuit :

In the given diagram, the resistors are in series connection,

So equivalent resistance = sum of resistance of both resistors.

\large \boxed{R_{eq} =R_1 +R_2  }

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Therefore, Equivalent resistance = 840 ohms.

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___________________________

\mathrm{ \#TeeNForeveR}

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