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k0ka [10]
3 years ago
7

Holden is trying to determine the velocity of his race car. He went 20 meters east, turned around, and went 40 meters west. He t

urned the car one more time and went 35 meters east. His car was 15 meters from the starting line. This took 5 seconds.
What is the car’s velocity?
A. 3 m/s west

B.3 m/s east

C. 19 m/s west

D. 19 m/s east
Physics
2 answers:
Volgvan3 years ago
6 0
Although the car's average speed is  19 m/s ,
its velocity is  3 m/s east.

Velocity is        (displacement) / (time)

and Displacement is the distance between the start point and
end point, no matter what route was traveled between them. 

In this case, the displacement is 15 meters east.
So the velocity is

               (15 meters east) / (5 sec) = 3 meters/sec east .
kupik [55]3 years ago
3 0

Although the car's average speed is  19 m/s ,

its velocity is  3 m/s east.

Velocity is        (displacement) / (time)

and Displacement is the distance between the start point and

end point, no matter what route was traveled between them. 

In this case, the displacement is 15 meters east.

So the velocity is

          Answer:    (15 meters east) / (5 sec) = 3 meters/sec east .

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Two airplanes leave an airport at the same time. The velocity of the first airplane is 730 m/h at a heading of 65.3 ◦ . The velo
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Answer:

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Explanation:

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So if we draw the vectors of a 2d graph we see that the difference in angles is   = 102^{\circ}-65.3^{\circ}=36.7^{\circ}

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So distance traveled by second plane = 590×1.7 = 1003 m

We represent these distances as two sides of the triangle, and the distance between the planes as the side opposing the angle 58.6.

Using the law of cosine, r^2 representing the distance between the planes, we see that:

r^2=1241^2+1003^2-2\times 1003\times 1241cos(36.7)=550112.8295

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3 0
3 years ago
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