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k0ka [10]
4 years ago
7

Holden is trying to determine the velocity of his race car. He went 20 meters east, turned around, and went 40 meters west. He t

urned the car one more time and went 35 meters east. His car was 15 meters from the starting line. This took 5 seconds.
What is the car’s velocity?
A. 3 m/s west

B.3 m/s east

C. 19 m/s west

D. 19 m/s east
Physics
2 answers:
Volgvan4 years ago
6 0
Although the car's average speed is  19 m/s ,
its velocity is  3 m/s east.

Velocity is        (displacement) / (time)

and Displacement is the distance between the start point and
end point, no matter what route was traveled between them. 

In this case, the displacement is 15 meters east.
So the velocity is

               (15 meters east) / (5 sec) = 3 meters/sec east .
kupik [55]4 years ago
3 0

Although the car's average speed is  19 m/s ,

its velocity is  3 m/s east.

Velocity is        (displacement) / (time)

and Displacement is the distance between the start point and

end point, no matter what route was traveled between them. 

In this case, the displacement is 15 meters east.

So the velocity is

          Answer:    (15 meters east) / (5 sec) = 3 meters/sec east .

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The answer is 7 hours
3 0
3 years ago
During a demonstration of the gravitational force on falling objects to her class, Sarah drops an 11 lb. bowling ball from the t
tia_tia [17]

1.A) 4.9 m  

AL2006 Ace

The instant it was dropped, the ball had zero speed.


After falling for 1 second, its speed was 9.8 m/s straight down (gravity).


Its AVERAGE speed for that 1 second was (1/2) (0 + 9.8) = 4.9 m/s.


Falling for 1 second at an average speed of 4.9 m/s, is covered 4.9 meters.


ANYTHING you drop does that, if air resistance doesn't hold it back.


Read more on Brainly.com - brainly.com/question/11776597#readmore

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5 0
3 years ago
Read 2 more answers
Compute the kinetic energy of a proton (mass 1.67×10−27kg ) using both the nonrelativistic and relativistic expressions for spee
JulsSmile [24]

Answer:

The non-relativistic kinetic energy of a proton is 6.76\times10^{-12}\ J

The relativistic kinetic energy of a proton is 7.25\times10^{-12}\ m/s

Explanation:

Given that,

Mass of proton m=1.67\times10^{-27}\ kg

Speed v= 9.00\times10^{7}\ m/s

We need to calculate the kinetic energy for non relativistic

Using formula of kinetic energy

K.E=\dfrac{1}{2}mv^2

Put the value into the formula

K.E=\dfrac{1}{2}\times1.67\times10^{-27}\times(9.00\times10^{7})^2

K.E=6.76\times10^{-12}\ J

We need to calculate the kinetic energy for relativistic

Using formula of kinetic energy

K.E=mc^2(\sqrt{(\dfrac{1}{1-\dfrac{v^2}{c^2}})}-1)

K.E=1.67\times10^{-27}\times(3\times10^{8})^{2}\cdot\left(\sqrt{\frac{1}{1-\frac{\left(9.00\times10^{7}\right)^{2}}{(3\times10^{8})^{2}}}}-1\right)

K.E=7.25\times10^{-12}\ m/s

Hence, The non-relativistic kinetic energy of a proton is 6.76\times10^{-12}\ J

The relativistic kinetic energy of a proton is 7.25\times10^{-12}\ m/s

7 0
3 years ago
A roadrunner is running along a straight desert road at a constant velocity of 25 m/s. If a certain coyote wants to capture the
andreyandreev [35.5K]

Answer:

t = 1.42 s and d = 35.5 m

Explanation:

Given that,

Velocity of a roadrunner is 25 m/s

A certain coyote wants to capture the roadrunner using a net dropped from an overpass that is 10 m high.

We need to find the time before the roadrunner is under the overpass and  how far away from the overpass is the roadrunner when the coyote drops the net.

d=ut+\dfrac{1}{2}at^2\\\\\text{Here, u = 0 and a = g}\\\\d=\dfrac{1}{2}gt^2\\\\t=\sqrt{\dfrac{2d}{g}} \\\\t=\sqrt{\dfrac{2\times 10}{9.8}} \\\\t=1.42\ s

Let d is the distance traveled. So,

d = vt

d = 25 m/s × 1.42 s

d = 35.5 m

5 0
3 years ago
Lead-202 has a half-life of 53,000 years. How long will it take for 15/16 of a sample of lead-202 to decay?
ohaa [14]

Answer:

C. 212,000 years

Explanation:

believe me it's correct.....and you're welcome :)

4 0
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