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Stels [109]
3 years ago
9

A Ferris wheel is turning at a constant speed of 5 m/s is it accelerating true or false?

Physics
1 answer:
NikAS [45]3 years ago
3 0

There are several things wrong with the question:

-- " 5 m/s " is not a turning speed.

-- 'Constant speed' can mean zero acceleration, or it can mean
huge acceleration if it's constant speed around a circle.  There's
not enough information here to tell the difference.
 
-- The answer to an "is it ?" question is 'yes' or 'no', not 'true' or 'false'.

All in all, this question is so ragged that any reliable answer
should probably be as negative as possible.

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The human ear canal is about 2.8 cm long. If it is regarded as a tube that is open at one end and closed at the eardrum, what is
Diano4ka-milaya [45]

Answer:

f = 3.1 kHz

Explanation:

given,

length of human canal =2.8 cm = 0.028 m

speed of sound = 343 m/s

fundamental frequency  = ?

The fundamental frequency of a tube with one open end and one closed end is,

f = \dfrac{v}{4L}

f = \dfrac{343}{4\times 0.028}

f = \dfrac{343}{0.112}

       f = 3062.5 Hz

       f = 3.1 kHz

hence, the fundamental frequency is equal to f = 3.1 kHz

8 0
3 years ago
a 46 kilogram student climbs 11 meter up a rope at a constant speed if the student power output is 230 watts how long in seconds
Bezzdna [24]
230×46=10580÷11=961 second
3 0
3 years ago
A 86 kg human stands on the surface of Venus. The mass of Venus is 4.9 × 1024 kg and its radius is 6.1 × 106 m. Collapse questio
iris [78.8K]

Answer:

755.37 N

Explanation:

We are given that

Mass of venus=m_1=4.9\times 10^{24}kg

Radius=r=6.1\times 10^6m

Mass of human=m_2=86 kg

We know that the gravitational force between two bodies

F=G\frac{m_1m_2}{r^2}

Where G=Gravitational constant=6.67\times 10^{-11}Nm^2/kg^2

Using the formula

The magnitude of the gravitational force exerted by Venus on the human=F=\frac{6.67\times 10^{-11}\times 86\times 4.9\times 10^{24}}{(6.1\times 10^6)^2}

The magnitude of the gravitational force exerted by Venus on the human=F=755.37N

7 0
3 years ago
Calculate the angle θ between the radius-vector of the point and the positive x axis (measured counterclockwise from the positiv
Y_Kistochka [10]

The point obviously is in the 3rs quadrant

So

စ= tan^-1( y/x)-180

စ= -89.7°

6 0
3 years ago
A sinusoidal transverse wave of amplitude ym = 8.4 cm and wavelength = 5.3 cm travels on a stretched cord. Find the ratio of the
Scilla [17]

Answer:

The ratio is 9.95

Solution:

As per the question:

Amplitude, y_{m} = 8.4\ cm

Wavelength, \lambda = 5.3\ cm

Now,

To calculate the ratio of the maximum particle speed to the speed of the wave:

For the maximum speed of the particle:

v_{m} = y_{m}\times \omega

where

\omega = 2\pi f = angular speed of the particle

Thus

v_{m} = 2\pi fy_{m}

Now,

The wave speed is given by:

v = f\lambda

Now,

The ratio is given by:

\frac{v_{m}}{v} = \frac{2\pi fy_{m}}{f\lambda}

\frac{v_{m}}{v} = \frac{2\pi \times 8.4}{5.3} = 9.95

8 0
3 years ago
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