Answer:
It would be 3 times as much gravity or 7 times
Explanation:
<span>Silver oxalate dissociation equation is following:
</span><span>
Ag</span>₂C₂O₄(s) ⇄ 2Ag⁺(aq) + C₂O₄²⁻(aq)
According to reaction follows next stoichiometric ratio:
[Ag⁺] : [C₂O₄²⁻] = 2 : 1
[C₂O₄²⁻] = [Ag⁺] / 2
[C₂O₄²⁻] = (1.7×10⁻⁴)/2 = 8.5×10⁻⁵ M
So, solubility product constants for silver oxalate is:
Ksp = [Ag⁺]² x [C₂O₄²⁻]
Ksp = [1.7×10⁻⁴]² x [8.5×10⁻⁵]
Ksp = 2.46×10⁻¹²
This is an exception to the general electronegativity trend. It can be explained by looking at the electron configurations of both elements.
<span>Be:[He]2<span>s2
</span></span><span>B:[He]2<span>s2</span>2<span>p1
</span></span>
When you remove an electron from beryllium, you are taking away an electron from the 2s orbital. When you remove an electron from boron, you are taking an electron from the 2p orbital. The 2p electrons have more energy than the 2s, so it is easier to remove them as they can more strongly resist the effective nuclear charge of the nucleus.
