<span>Lithium has a property
of high reactivity and to obtain lithium is through electrolysis of its fused
salts. Because lithium is very reactive, it is not found free so electrolysis
is use to split it apart to get it. Moreover,
Lithium is an alkali metal with single valence electron that is easily given up
to form cation, which make it a good conductor of heat and electricity.</span>
<span> </span>
<span>Benzoin<span> is an organic compound with the formula PhCH(OH)C(O)Ph. It is
a hydroxy ketone attached to two phenyl groups.</span><span>
To answer your question, </span><span>the balanced oxidation-reduction reaction equation for the
oxidation of benzoin by ammonium nitrate is:
</span>2Ph-C(OH)-C(O)-Ph+NH4NO3
--> 2Ph-C(O)-C(O)-Ph + N2 + 3H2O.</span>
<span>
</span><span>I hope this helps and if you have any
further questions, please don’t hesitate to ask again.</span>
Answer:
The conversion achieved for the first CSTR impeller is 0.382
Discrepancy = 0.188
Explanation:
The impeller divides the CSTR into 2 equal reactors of volume 500gal
Using V = FaoX/ (-ra)
500gal = Fao×Xa/[(KCao^2( 1 -X1)^2]
500gal = CaoVoX1/ KCao^2(1-X1)
500gal= 500gal × X1'/(1 - X1)^2
(1 -X1)^2 = X1
X1^2 - 3X1 + 1 = 0
X1= 0.382
Conversion achieved in the first CSTR is 0.382
Actual measured CSTR = 57% =57/100=0.57
Discrepancy in the conversions= 0.57 -0.383 =0.188
Answer:
(a) 
(b) Rubidium
Explanation:
Hello,
This titration is carried out by assuming that the volume of base doesn't have a significant change when the mass is added, thus, we state the following data a apply the down below formula to compute the molarity of the base solution:
Solving for the molarity of base we've got:
Now, we can compute the moles of the base as:
(a) Now, one divides the provided mass over the previously computed moles to get the molecular mass of the unknown base:
(b) Subtracting the atomic mass of oxygen and hydrogen, the metal's atomic mass turns out into:
So, that atomic mass dovetails to the Rubidium's atomic mass.
Best regards.
