A.) We use the famous equation proposed by Albert Einstein written below:
E = Δmc²
where
E is the energy of the photon
Δm is the mass defect, or the difference of the mass before and after the reaction
c is the speed of light equal to 3×10⁸ m/s
Substituting the value:
E = (1.01m - m)*(3×10⁸ m/s) = 0.01mc² = 3×10⁶ Joules
b) The actual energy may be even greater than 3×10⁶ Joules because some of the energy may have been dissipated. Not all of the energy will be absorbed by the photon. Some energy would be dissipated to the surroundings.
Answer:
W = y (b-a) / ab
Explanation:
Work is defined by the expression
W = ∫ F. dr
In this case the force is in the same direction of displacement, so the scalar product is reduced to the ordinary product
W = ∫ F dr
The expression of the strength left is
F = -y / x²
let's replace and integrate
W = ∫ (-y / x²) dx
W = -y (-1 / x)
We evaluate between the lower limit x = b + a to the upper limit x = 0 + a
W = -y (-1 / b + 1 / a)
W = y (b-a) / ab
where (b-a) is the distance traveled
Explanation:
Simply, shake the boxes. The box that is difficult to shake will be the sand and the box that will be easier will be the feathers.
Answer:
The heat is 10458 J and 15480 J.
Explanation:
Given that,
Temperature T₁ = 404 K
Temperature T₂ = 298 K
Work done = 2740 J
If the temperature T₁ =298 k
Temperature T₂ = 245 K
We need to calculate the heat
Using efficiency formula
...(I)
We need to calculate the efficiency
Using formula of efficiency
Put the value of efficiency in equation (I)
Again, we need to calculate the efficiency
We need to calculate the heat
Using equation (I)
Hence, The heat is 10458 J and 15480 J.
