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topjm [15]
2 years ago
9

What is a random motion ​

Physics
2 answers:
Leokris [45]2 years ago
7 0

Answer:

Random Motion is a motion in which an object didn't go in a straight manner, for ex: zig zag lines, curved, etc.

Explanation:

saw5 [17]2 years ago
7 0
When an object does not go in a straight motion such as when it curves or something like that.
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PLEASE HELP 100 POINTS! Please fill in the scale distance from sun and diversion factor, listing off the numbers works
steposvetlana [31]

Solved your another question same like this with scaling to Cm this time we go with metre(m)

Scale factor

  • 1km=10³m
  • 1m=10^{-3}km

Mercury

  • 58000m

Ven us

  • 108000m

Earth

  • 150000m

Mars

  • 228000m

Jupiter

  • 778000m

Saturn

  • 1430000m

Uranus

  • 2870000m

Neptune

  • 4500000m

7 0
2 years ago
You want to make a ride so you do not want to exceed 1.1g’s, if the radius of the turns are 10m, then what is the maximum speed
Citrus2011 [14]

The maximum speed is 10.4 m/s

Explanation:

For a body in uniform circular motion, the centripetal acceleration is given by:

a=\frac{v^2}{r}

where

v is the linear speed

r is the radius of the circular path

In this problem, we have the following data:

- The maximum centripetal acceleration must be

a=1.1 g

where g=9.8 m/s^2 is the acceleration of gravity. Substituting,

a=(1.1)(9.8)=10.8 m/s^2

- The radius of the turn is

r = 10 m

Therefore, we can re-arrange the equation to solve for v, to find the maximum speed the ride can go at:

v=\sqrt{ar}=\sqrt{(10.8)(10)}=10.4 m/s

Learn more about centripetal acceleration:

brainly.com/question/2562955

#LearnwithBrainly

8 0
3 years ago
he block is released, and it slides 2.0 m (from the point at which it is released) across a horizontal surface before friction s
alex41 [277]

Answer:

0.245

Explanation:

When the block is released, the initial elastic potential energy stored in the spring is entirely converted into kinetic energy of the block.

Therefore, we can calculate the initial speed of the block:

\frac{1}{2}kx^2 = \frac{1}{2}mv^2

where the term on the left is the potential energy and where the term on the right is the kinetic energy, and where

k = 4500 N/m is the spring constant

x = 8.0 cm = 0.08 m is the compression of the spring

m = 3.0 kg is the mass of the block

v is the initial velocity

Solving for v,

v=\sqrt{\frac{kx^2}{m}}=\sqrt{\frac{(4500)(0.08)^2}{3.0}}=3.1 m/s

Then, after the block is released, all its kinetic energy is converted into thermal energy as the block slows down, due to friction. Therefore, the work done by friction is equal to the initial kinetic energy of the block.

The force of friction is

F=\mu mg

where

\mu is the coefficient of friction

g=9.8 m/s^2 is the acceleration of gravity

So the work done by it is (in magnitude)

W=Fd=\mu mg d

where

d = 2.0 m is the distance covered

Therefore,

\frac{1}{2}mv^2 = \mu mg d

And solving for \mu,

\mu = \frac{v^2}{2gd}=\frac{3.1^2}{2(9.8)(2.0)}=0.245

8 0
3 years ago
If i jump on a trampoline. is it an inelastic or elastic collision?
Sladkaya [172]
Inelastic Collision :P
5 0
3 years ago
Read 2 more answers
How much time will it take for a bug to travel 2 meters across the floor if it is traveling at 0.5 m/s?
7nadin3 [17]
4 seconds to travel 2 meters :)
6 0
2 years ago
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