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ycow [4]
4 years ago
12

You decide to build a small generator by rotating a coiled wire inside a static magnetic field of 0.30 T. You construct the appa

ratus by coiling wire into 5 loops of radius 0.18 m. If the coils rotate at 2.0 revolutions per second and are connected to a device with 120Ω resistance, calculate the average power Paverage supplied to that device.
Physics
1 answer:
Mekhanik [1.2K]4 years ago
6 0

Answer:0.0153 W

Explanation:

Given

Magnetic Field B=0.3 T

N=5

radius R=0.18 m

N_0=2 rps

\omega =2\pi N_0=12.56 rad/s

flux associated with loop is

\phi _B=NBA\cos \theta

\phi _B=NBA\cos \omega t

and Induced emf is

e=\frac{\mathrm{d} \phi _B}{\mathrm{d} t}

e=NBA\omega \sin \omega t

and let Q be the energy dissipated then

Q=\int Pdt

Q=\int_{0}^{T}\frac{E^2}{R}dt

Q=\frac{(NBA\omega )^2}{R}\int_{0}^{T}\frac{1-\cos 2\omega t}{2}dt

Q=\frac{(NBA\omega )^2}{R}\times \frac{T}{2}

Thus \frac{Q}{T}=P_{avg}

P_{avg}= \frac{(NBA\omega )^2}{2R}

P_{avg}=\frac{(5\times 0.3\times 0.101/8\times 12.56)^2}{2\times 120}

P_{avg}=0.0153 W

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First find ( volume) ;

v =  \frac{4}{3} \pi \:  {r}^{3}  \\  \\ v =  \frac{4}{3}  \times 3.14 \times ( {0.875)}^{3}  \\  \\ v =  \frac{4}{3}   \times 3.14 \times 0.66992187  \:  {cm}^{3} \\  \\ v = 2.8 \:  {cm}^{3}

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I hope I helped you^_^

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How do you do this problem?
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Unless indicated otherwise, assume the speed of sound in air to be v = 344 m/s. A stationary police car emits a sound of frequen
bixtya [17]

Answer:

a) The velocity of the car is 7.02 m/s and the car is approaching to the police car as the frequency of the police car is increasing.

b) The frequency is 1404.08 Hz

Explanation:

If the police car is a stationary source, the frequency is:

f_{a} =(\frac{v+v_{c} }{v} )f_{s} (eq. 1)

fs = frequency of police car = 1200 Hz

fa = frequency of moving car as listener

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vc = speed of moving car

If the police car is a stationary observer, the frequency is:

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Now,

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b) Substitute eq. 1 in eq. 2:

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7 0
4 years ago
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