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Harrizon [31]
3 years ago
12

Without using Desmos what is the complete factorization of 2x^2+x-15? Please show work , please help

Mathematics
1 answer:
andrezito [222]3 years ago
4 0
The last one x+5 2x-3
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weqwewe [10]

Sry couldn't find the answer

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3 years ago
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What is the value of r
seropon [69]

Answer:

r = 57

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Is the system of equations is consistent, consistent and coincident, or inconsistent?
valentinak56 [21]

Answer:

consistent

Step-by-step explanation:

Here we are given two equations.

Y = -3x + 12

Y  = -6x + 2

First let's see the definition of consistent and inconsistent.

If a system has at least one solution, it is said to be consistent .

If a consistent system has exactly one solution, it is independent .

If a consistent system has an infinite number of solutions, it is dependent . When you graph the equations, both equations represent the same line.

If a system has no solution, it is said to be inconsistent . The graphs of the lines do not intersect, so the graphs are parallel and there is no solution.

Let's solve this equations

-3x + 12 = -6x + 2

6x - 3x = 2 -12

3x = -10

x = -10/3

Now plug in x = -10/3 in the first equation to get the value of y.

y = -3*-10/3 + 12

y = 10 + 12

y = 22

Therefore, the system has exactly one solution at (-10/3, 22).

If a system has at least one solution, it is said to be consistent .

Therefore, answer is consistent.

Hope this will helpful.

Thank you.

7 0
4 years ago
What is the value of x?
Svetllana [295]

Answer:

x = 4

Step-by-step explanation:

ΔTRQ is an isosceles right triangle, so if we find the value of RT then the value of 'x' will be the same

We can find RT by creating a proportion based on the ratio of sides in a 30-60-90° triangle which, respectively, is 1 : \sqrt{3} : 2

2\sqrt{3}/RT = \sqrt{3}/2

cross-multiply:

\sqrt{3}· RT = 4\sqrt{3}

RT = 4

Therefore, x = 4

3 0
3 years ago
How do you read this number? .1237
andrezito [222]

Answer:

Step-by-step explanation:

One thousand, two hundred thirty seven ten thousandths

5 0
3 years ago
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