Dry air will break down if the electric field exceeds about 3.0×106v/m. part a what amount of charge can be placed on a capacito r if the area of each plate is 5.5 cm2 ? express your answer using two significant figures.
1 answer:
The solution for this problem is:The charge would be now equal to:(electric constant) multiplied by the (field strength) multiplied by the (area) so plugging in our values, will give us:8.85 * 10^-12 As / (V * m) * 3 * 10^6 V/m * 0.055 m^2 = 1.46 e-6 amperes would be the answer
You might be interested in
Bouta catch these free points lmaoooo hey grace Im right next to you lololololol
Answer:
4.3 cm
Explanation:
We are given that
Width,d=70.3
Wavelength,
We have to find the width in cm of the pattern.
The angle for the first minimum m=1
The width of the pattern=
Explanation:
I b e l i e v e <u>f</u> <u>i</u> <u>l</u> <u>m</u> <u> </u> <u>i</u> <u>s</u> <u> </u> n o t p a r t o f a c i r c u i t
Answer:
7.4 cm
Explanation:
K = 2.17 x 10^3 N/m
m = 4.71 kg
v = 1.78 m/s (It is maximum velocity)
The angular velocity
ω = 24 rad/s
Maximum velocity, v = ω x A
Where, A be the maximum displacement
1.78 = 24 x A
A = 0.074 m = 7.4 cm
Resistivity of nichrome is high.
