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masya89 [10]
3 years ago
14

Dry air will break down if the electric field exceeds about 3.0×106v/m. part a what amount of charge can be placed on a capacito

r if the area of each plate is 5.5 cm2 ? express your answer using two significant figures.
Physics
1 answer:
Genrish500 [490]3 years ago
7 0
The solution for this problem is:The charge would be now equal to:(electric constant) multiplied by the (field strength) multiplied by the (area) so plugging in our values, will give us:8.85 * 10^-12 As / (V * m) * 3 * 10^6 V/m * 0.055 m^2 = 1.46 e-6 amperes would be the answer
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A parallel-plate capacitor has a plate area of 0.2m^2 and a plate separation of 0.1mm. To obtain an electric field of 2.0 × 10^6
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Answer:

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Hence the magnitude of the charge on each plate should be 3.536*10^-6 C

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