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4 years ago

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What does matter make up

1 answer:

Gnoma [55]4 years ago

7 0

any thing which has mass and occupie some space is called matter

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A coil 3.95 cm radius, containing 520 turns, is placed in a uniform magnetic field that varies with time according to B=( 1.20×1

Pie

Answer:

(a) E= 3.36×10−2 V +( 3.30×10−4 V/s3 )t3

(b) $I=0.0085\ A$

Explanation:

Given:

radius if the coil, $r=0.0395\ m$

no. of turns in the coil, $n=520$

variation of the magnetic field in the coil, $B=(1.2\times 10^{-2})t+(3.45\times 10^{-5})t^4$

resistor connected to the coil, $R=560\ \Omega$

(a)

we know, according to Faraday's Law:

$emf=n.\frac{d\phi}{dt}$

where:

$d \phi=$ change in associated magnetic flux

$\phi= B.A$

where:

A= area enclosed by the coil

Here

$A=\pi.r^2$

$A=\pi\times 0.0395^2$

$A=0.0049\ m^2$

$\therefore \phi=((1.2\times 10^{-2})t+(3.45\times 10^{-5})t^4)\times 0.0049$

So, emf:

$emf= 520\times \frac{d}{dt} [((1.2\times 10^{-2})t+(3.45\times 10^{-5})t^4)\times 0.0049]$

$emf= 520\times 0.0049\times \frac{d}{dt} [(1.2\times 10^{-2})t+(3.45\times 10^{-5})t^4)]$

$emf= 2.548\times [0.012+(13.8\times 10^{-5})t^3)]$

$emf= 0.0306+3.516\times 10^{-4}\ t^3$

(b)

Given:

$t_0=5.25\ s$

Now, emf at given time:

$emf=4.7755\times 10^{-2}\ V$

∴Current

$I=\frac{emf}{R}$

$I=\frac{4.7755\times 10^{-2}}{560}$

$I=8.5\times 10^{-5} A$

6 0

4 years ago

13.00 cm + 2.56 mm + 0.0047= cm? Solve problem with correct number of significant digits

Drupady [299]

The answer is 13.2607 cm

7 0

3 years ago

Read 2 more answers

Two charged plates separated by 15 cm create a uniform electric field of 360 n/c. what is the potential difference between the p

nikitadnepr [17]

When two charged plates are separated by a distance, the potential difference between the plates is 54 Volts.

<h3>What is uniform electric field?</h3>

The electric field intensity which does not increase or decrease with time or remain constant is called the uniform electric field.

Given is the plates separated by distance d = 15 cm =0.15 m, electric field E= 360 N/C.

The relation between the electric field and voltage is

E=V/d

Substitute the values into the expression to get the potential difference V,

V = 360 x 0.15

V = 54 Volts

Thus, the potential difference between the plates is 54 Volts.

Learn more about uniform electric field.

brainly.com/question/26446532

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8 0

3 years ago

Increasing the pitch of a note on the piano means you make the note

julia-pushkina [17]

Increasing the pitch makes a note higher

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3 years ago

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An amoeba has 1.00×1016 protons and a net charge of 0.300 pC. (a) How many fewer electrons are there than protons? (b) If you pa

ladessa [460]

Explanation:

(a) It is known that charge on a proton is equal to $1.6 \times 10^{-19} C$ . And, net charge is given as $0.3 pC$ which is also equal to $0.3 \times 10^{-12}C$ .

Therefore, we will calculate the number of electrons as follows.

$\frac{0.3 \times 10^{-12}C}{1.6 \times 10^{-19}C}$

= $1.87 \times 10^{6}$

Hence, there are $1.87 \times 10^{6}$ fewer electrons are there than protons.

(b) Now, we will calculate the fraction of protons that would have no electrons as follows.

$\frac{1.88 \times 10^{6}}{1 \times 10^{16}}$

= $1.88 \times 10^{-10}$

Therefore, fraction of the protons that would have no electrons is $1.88 \times 10^{-10}$ .

3 0

3 years ago