Answer:
0.34 sec
Explanation:
Low point of spring ( length of stretched spring ) = 5.8 cm
midpoint of spring = 5.8 / 2 = 2.9 cm
Determine the oscillation period
at equilibrum condition
Kx = Mg
g= 9.8 m/s^2
x = 2.9 * 10^-2 m
k / m = 9.8 / ( 2.9 * 10^-2 ) = 337.93
note : w =
=
= 18.38 rad/sec
Period of oscillation = 
= 0.34 sec
Don't text while driving
don't get your eyes off the road
don't get distracted
Answer:
T is less than or equal to 19 N
Explanation:
Answer:

Explanation:
Given:
- area of piston on the smaller side of hydraulic lift,

- area of piston on the larger side of hydraulic lift,

- Weight of the engine on the larger side,

Now, using Pascal's law which state that the pressure change in at any point in a confined continuum of an incompressible fluid is transmitted throughout the fluid at its each point.



is the required effort force.