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3 years ago

11

Geoff was charging his phone and wanted to know how many amperes were entering his phone. What was Geoff trying to measure? A. l

ength B. volume C. brightness D. current

1 answer:

hram777 [196]3 years ago

5 0

Hello!

Geoff was trying to measure D) current.

I hope it helps!

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How do the magnetic poles of earth serve to protect life on earth?

SCORPION-xisa [38]

Answer:

The block solar winds and other harmful things

Explanation:

The Earth's magnetic field serves to deflect most of the solar wind, whose charged particles would otherwise strip away the ozone layer that protects the Earth from harmful ultraviolet radiation.

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3 years ago

Read 2 more answers

The CERN particle accelerator is circular with a circumference of 7.0 km.

Contact [7]

Answer:

$a_c=2.0196\times 10^{13}\ m/s^2$

$F=3.37273\times 10^{-14}\ N$

Explanation:

m = Mass of proton = $1.67\times 10^{-27}\ kg$

v = Speed of proton = 0.5c = $0.5\times 3\times 10^8=1.5\times 10^8\ m/s$

Circumference of the colider is 7 km

$P=2\pi r\\\Rightarrow r=\frac{P}{2\pi}\\\Rightarrow r=\frac{7000}{2\pi}\ m$

$a_c=\frac{v^2}{r}\\\Rightarrow a_c=\frac{\left(1.5\times 10^8\right)^2}{\frac{7000}{2\pi}}\\\Rightarrow a_c=2.0196\times 10^{13}\ m/s^2$

Centripetal acceleration is $2.0196\times 10^{13}\ m/s^2$

$F_c=ma_c\\\Rightarrow F_c=1.67\times 10^{-27}\times 2.0196\times 10^{13}\\\Rightarrow F=3.37273\times 10^{-14}\ N$

Force on protons is $3.37273\times 10^{-14}\ N$

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4 years ago

If the primary to secondary voltage ratio is 4:1 for a transformer, what is the secondary voltage if the primary voltage is 460

Vesnalui [34]

<h2>The secondary voltage is 115 V.</h2>

Explanation:

The primary to secondary voltage ratio is given as 4:1 .

That is

$\frac{V_p}{V_s}=\frac{4}{1}=4$

We need to find what is the secondary voltage if the primary voltage is 460 volts.

That is

$V_p=460V$

Substituting in ratio equation

$\frac{V_p}{V_s}=4\\\\\frac{460}{V_s}=4\\\\V_s=\frac{460}{4}\\\\V_s=115V$

The secondary voltage is 115 V.

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3 years ago

Use the equation in the sample problem on the previous page to find the area of a rectangle that is 48.5 cm long and 3.77 cm wid

notka56 [123]

AREA=L*B
A=3.77*48.5
A=

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3 years ago

A constant force of 53 newtons was applied to a 12-kilogram mass for 15 seconds. a.) What was the change in momentum of the mass

vazorg [7]

Explanation:

Impulse = change in momentum

FΔt = Δp

(53 N) (15 s) = Δp

Δp = 795 kg m/s

For constant mass:

Δp = m Δv

795 kg m/s = (12 kg) Δv

Δv = 66.25 m/s

Rounding to two significant figures, Δp = 800 kg m/s and Δv = 66 m/s.

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3 years ago