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Nezavi [6.7K]
3 years ago
13

HELP ASAP PLEASE!!!

Chemistry
1 answer:
fenix001 [56]3 years ago
4 0

Answer:

  • Because<em> alkenes and alkynes</em> are defined as molecules with at least one double (in the case of alkenes) or triple (in the case of alkynes) bond between two carbon atoms, while alkanes have only single bonds between any pair of carbon atoms.

Explanation:

<em>Alkenes</em> and <em>alkynes</em> are unsaturated molecules, because they have, at least, two adjacent carbon atoms bonded together by either a doubler or a triple bond: - C = C -  or - C ≡ C -.

Hence, at least two carbon atoms are needed to form those double or triple bonds, while alkanes have only single bonds. The example of alkane with only one carbon atom is methane: CH₄, which is the most simple alkane.

The most simple alkene is CH₂ = CH₂, and the most simple alkyne is CH≡CH.

As you see, the very definition of alkenes and alkynes forces that those molecules must have at least two carbon atoms.

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Below are the steps of the engineering process (not necessarily in order): 1) Know the background 2) Do the work 3) Make a plan
LuckyWell [14K]

Answer:

4 - 1 - 3 - 2 - 6 - 5

Explanation:

During an engineering process, first, we need to identify the problem, or the need because the process only will occur because of some need. Then, it's necessary to know as much as possible about the problem and the things that already exist or already were tested to solve it. Knowing the background will make the work easy.

After that, it's necessary to plan the things we'll do, knowing the costs, the time needed for activities, how many people will be necessary for each step, etc. It's really important to make a plan. Then, do the work, following the plan. Thus, the process must be tested. During the test of the results, some problems must be found, so it's time to evaluate and redesign the process, to solve these problems found.

3 0
3 years ago
A 50.5 L flask contains 3.25 mol of an unknown gas at 288.6 K, what is the pressure of<br> this gas?
Ivahew [28]

Answer:

1.52atm is the pressure of the gas

Explanation:

To solve this question we must use the general gas law:

PV = nRT

<em>Where P is pressure in atm = Our incognite</em>

<em>V is volume = 50.5L</em>

<em>n are moles of gas = 3.25moles</em>

<em>R is gas constat = 0.082atmL/molK</em>

<em>And T is absolute temperature = 288.6K</em>

To solve pressure:

P = nRT / V

P = 3.25mol*0.082atmL/molK*288.6K / 50.5L

P = 1.52atm is the pressure of the gas

3 0
2 years ago
How many moles are there in 35.2g of Gold?
ki77a [65]

Explanation:

196.96655

maybe

5 0
3 years ago
aseous methane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 5.5 g of methane is
maksim [4K]

Answer:

There is 9.6 grams of CO2 produced

Explanation:

Step 1: Data given

Mass of methane = 5.50 grams

Molar mass of methane = 16.04 g/mol

Mass of oxygen = 13.9 grams

Molar mass of oxygen = 32.0 g/mol

Step 2: The reaction

CH4(g) + 2O2(g) → CO2(g) + 2H2O(g)

Step 3: Calculate number of moles

Moles = mass / molar mass

Moles methane = 5.50 grams / 16.04 g/mol

Moles methane = 0.343 moles

Moles oxygen = 13.9 grams / 32.0 g/mol

Moles oxygen = 0.434 moles

For 1 mol CH4 we need 2 moles O2 to produce 1 mol CO2 and 2 moles H2O

O2 is the limiting reactant. It will completely react (0.434 moles).

There will react 0.434/2 = 0.217 moles CH4

There will remain 0.343-0.217 = 0.126 moles CH4

There will be produced 0.434 moles of H2O and

0.434/2 =0.217 moles of CO2

Step 4: Calculate mass of products

Mass = moles * molar mass

Mass CO2 = 0.217 moles ¨44.01 g/mol

Mass CO2 = 9.6 grams

Mass H2O = 0.434 moles * 18.02

Mass H2O = 7.8 grams

4 0
2 years ago
Pls help me ASAP <br>its very urgent ​
vovikov84 [41]

Answer:

C Region

Explanation:

C Region contains all the liquids as 0 °C is the freezing point of water (Crystals of water are formed leaving it no more in the liquid state) and 100 °C is the boiling point (The water boils leaving it no more in the liquid state).

Hence, All liquids are contained in the C region.

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
8 0
3 years ago
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