6 sodium and 6 Bromine in 6NaBr
Answer:
The water potential of a solution of 0.15 M sucrose solution is -3.406 bar.
Explanation:
Water potential = Pressure potential + solute potential


We have :
C = 0.15 M, T = 273.15 K
i = 1
The water potential of a solution of 0.15 m sucrose= 
(At standard temperature)


The water potential of a solution of 0.15 M sucrose solution is -3.406 bar.
Isoflavones, quercetin, and anthocyanin are all Flavonoids.
Mixtures come in many forms and phases. Most of them can be separated, and the kind of separation method depends on the kind of mixture it is. Below are some common separation methods:
Answer:
<h3>The answer is 4.15 g/mL</h3>
Explanation:
The density of a substance can be found by using the formula

From the question
mass of object = 8.3 g
volume = final volume of water - initial volume of water
volume = 8 - 6 = 2 mL
So we have

We have the final answer as
<h3>4.15 g/mL</h3>
Hope this helps you