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vivado [14]
3 years ago
7

ILL GIVE BRAINLIEST I NEED THE ANSWER RIGHT AWAY PLEASE SOMEONE

Chemistry
1 answer:
Archy [21]3 years ago
5 0

Answer:

ILL GIVE BRAINLIEST I NEED THE ANSWER RIGHT AWAY PLEASE SOMEONE

For each of the following processes that show the formation of ions, complete the process by indicating

the number of electrons that must be gained or lost

to form the ion. Indicate the total number of electrons in the ion, and in the atom from which it was

made.

a. Al S Al3 d. F S F

b. S S S2 e. Zn S Zn2

c. Cu S Cu f. P S P3

77. For each of the following atomic

Explanation:

ILL GIVE BRAINLIEST I NEED THE ANSWER RIGHT AWAY PLEASE SOMEONE

For each of the following processes that show the formation of ions, complete the process by indicating

the number of electrons that must be gained or lost

to form the ion. Indicate the total number of electrons in the ion, and in the atom from which it was

made.

a. Al S Al3 d. F S F

b. S S S2 e. Zn S Zn2

c. Cu S Cu f. P S P3

77. For each of the following atomic

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8 0
2 years ago
According to the following balanced equation, 2 formula units of Iron (III) Oxide (Fe2O3) can be formed by reacting 4 atoms of i
-Dominant- [34]
You have to use Avogadro's number (6.02x10^23 molecules/mole) to find the number of moles each reactant starts off with.
moles of Fe and O₂:
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6 molecules/(6.02x10^23 molecules/mole)=9.967x10^-24 mol <span>O₂
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amount of Fe₂O₃ produced:
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</span>since oxygen produces the leas amount of product, oxygen is the limiting reagent.  since we know that oxygen is the limiting reagent we can use the amount of product formed with oxygen to find the amount of iron used.
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</span>1.993x10^-23-1.329x10^-23= 6.645x10^-23mol Fe left
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I hope this helps.
8 0
2 years ago
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3 years ago
What is the pH of a 2.0 x 10^-4 M solution of nitric acid (HNO3)
Semmy [17]

Hello!

datos:

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ps: The ionization constant of the nitric acid is strong (100% ionized in water) or completely dissociates in water, so the pH will be:

pH = - log\:[H_3O^+]

pH = - log\:[2*10^{-4}]

pH = 4 - log\:2

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\boxed{\boxed{pH = 3.70}}\end{array}}\qquad\checkmark

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I Hope this helps, greetings ... DexteR!

3 0
3 years ago
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