All categories

3 years ago

In a redox reaction, oxidation is defined by the:

Chemistry

1 answer:

vodomira [7]3 years ago

5 0

Answer:

Option 4. loss of electrons, resulting in an increased oxidation number.

Explanation:

Oxidation is a process involving loss of electron(s). When this happens the oxidation number of the atom being oxidised increases. This can be seen when calcium (Ca) reacts with chlorine (Cl2) to form calcium chloride (CaCl2) according to the equation given below:

Ca + Cl2 —> CaCl2

The oxidation number of calcium increases from 0 to +2. This implies that calcium is being oxidised as it loses its electrons. The oxidation number of chlorine decreases from 0 to - 1 as it gains electron.

Now, we can see that the oxidation of calcium i.e lose of electrons increased its oxidation number from 0 to +2.

From the simple illustrations above, we can see clearly that oxidation involves loss of electrons, resulting in an increased oxidation number.

You might be interested in

Which of the following statements correctly describes boyle's law

abruzzese [7]

In the said law, the volume of a gas varies inversely with pressure. Boyle's law is one of the gas laws we have. According to this law, at a fixed amount of an ideal gas which is at constant temperature, the pressure and volume are inversely proportional with each other. The variables are volume and pressure.

3 0

3 years ago

How does the abundance of various isotopes affect the atomic mass?

eduard

solution:

The quoted atomic mass on the Periodic Table is the WEIGHTED average of the individual isotopic masses. The higher the isotopic percentage, the MORE that isotope will contribute to the isotopic mass. For this reason, most masses that are quoted on the Table are non-integral.

By way of example we could look to the hydrogen atom. The VAST majority of hydrogen atoms (in this universe) are the protium isotope. i.e. 1H, whose nuclei contain JUST the defining proton. There is a smaller percentage (>1%) of hydrogen atoms WITH one NEUTRON in their nuclei to give the deuterium isotope. i.e. 2H, and because this is relatively cheap, and easily incorporated into a molecule, deuterium labelling is routinely used in analysis.

And there is even a smaller percentage of hydrogen atoms with TWO NEUTRONS in their nuclei, to give the tritium isotope. i.e. 3H. The weighted average of the isotopic percentages gives $1.00794⋅g⋅mol^{−1}$

6 0

3 years ago

AlCl3 + Na NaCl + Al Did Na change oxidation number?

Ilya [14]

$Al^{+III}Cl^{-I} _{3}+Na^{0}\rightarrow Na^{+I}Cl^{-I} + Al^{0}\\\\
Yes$

3 0

4 years ago

What is the formula for calcium chloride? Ca2Cl CaCl CaCl2 CaCl3

djyliett [7]

Hello there, and thank you for asking your question here on brainly.

The answer to this is Answer choice C: CaCl2

Hope this helped you! ♥

8 0

4 years ago

Read 2 more answers

One of the compounds used to increase the octane rating of gasoline is toluene (pictured). Suppose 43.3 mL of toluene (d = 0.867

Thepotemich [5.8K]

Answer:

(A)

Density = Mass / Volume

Mass = Density × Volume

$= 0.867 g/mL \times 43.3mL = 37.5411 g Toluene$

$1C_6 H_5 CH_3 + 9 O_2 > 7 CO_2 + 4 H_2 O$

Mole ratio of toluene : Oxygen is 1 : 9

$37.5411 g \text { Toluene } \times \frac{1 \text {mol} \text {toluene}}{92 g \text { toluene}} \times \frac{9 {mol} O_{2}}{1 \text {mol} \text { toluene }} \times \frac{32 g O_{2}}{1 {mol} O_{2}}=117 g O_{2}(\text {Answer})$

(B)

1 mole of Toluene produces 7 moles of $CO_2$ gas and 4 moles of $H_2 O$ Vapour

So the mole ratio is 1 : 11

$37.5411 g Toluene $\times \frac{1 \text { mol toluene }}{92 g \text { toluene }} \times \frac{11 \mathrm{mol} \text { gas }}{1 \text { mol toluene }} $$\\\\=4.49 \text { mol gaseous products (Answer) } $$

(C)

1mole contains $6.022\times10^{23}$ molecules

$37.5411 g Toluene $\times \frac{1 \text { mol toluene }}{92 g \text { toluene}} \times \frac{4 \mathrm{mol} \mathrm{H}_{2} \mathrm{O}}{1 \mathrm{mol} \text { toluene }} \times \frac{6.022 \times 10^{23} \text { molecules } \mathrm{H}_{2} \mathrm{O}}{1 \mathrm{mol} \mathrm{H}_{2} \mathrm{O}} $\\\\$=9.82 \times 10^{23} \text { molecules } \mathrm{H}_{2} \mathrm{O} \text { (Answer) } $$

6 0

4 years ago