Answer:
A. The concentration of H+ is 0.0025 M
B. The pH is 2.6
C. The concentration of OH- is 3.98x10^-12 M
Explanation:
We'll begin by writing the balanced
dissociation equation of HClO4. This is illustrated below:
HClO4 —> H+ + ClO4-
A. Determination of the concentration of H+ in 0.0025 M HClO4. This is illustrated below:
From the balanced equation above,
1 mole of HClO4 produced 1 mole of H+.
Therefore, 0.0025 M of HClO4 will also produce 0.0025 M of H+.
The concentration of H+ is 0.0025 M
B. Determination of the pH.
The pH of the solution can be obtained as follow:
The concentration of H+, [H+]
= 0.0025 M
pH =?
pH = - log [H+]
pH = - log 0.0025
pH = 2.6
C. Determination of the concentration of OH-
To obtain the concentration of OH-, we must first calculate the pOH of the solution. This is illustrated below:
pH + pOH = 14
pH = 2.6
pOH =?
pH + pOH = 14
2.6 + pOH = 14
Collect like terms
pOH = 14 - 2.6
pOH = 11.4
Now, we can calculate the concentration of the OH- as follow:
pOH = - Log [OH-]
pOH = 11.4
11.4 = - Log [OH-]
- 11.4 = log [OH-]
[OH-] = anti log (- 11.4)
[OH-] = 3.98x10^-12 M
