How are igneous rocks formed?

The formation of tert-butanol is described by the following chemical equation:

fomenos

Answer:

Second step

(CH3)3C+ (aq) + OH^-(aq) ------->(CH3)3COH(aq)

Explanation:

This reaction involves;

First the ionization of the tertiary halide to firm a carbocation

Secondly the attack of the hydroxide ion on the carbocation to form tert-butanol

First step;

(CH3)3CBr (aq) → (CH3)3C+ (aq) + Br- (aq)

Second step

(CH3)3C+ (aq) + OH^-(aq) ------->(CH3)3COH(aq)

This second step completes the reaction mechanism.

3 0

3 years ago

En la reacción I2(g) + Br2(g) « 2 IBr(g), Keq = 280 a 150°C. Suponga que se permite que 0.500 mol de IBr en un matraz de 1.00 L

love history [14]

Answer:

P IBr: 15.454atm

I₂: 0.923 atm

P Br₂: 0.923atm

Explanation:

Basados en la reacción:

I₂(g) + Br₂(g) ⇄ 2 IBr(g)

La constante de equilibrio, Keq, es definida como:

$Keq = \frac{P_{IBr}^2}{P_{I_2}P_{Br_2}}$

Se cumple la relación de Keq = 280 cuando las presiones están en equilibrio

Usando PV = nRT, la presión inicial de IBr es:

P = nRT / V; 0.500mol*0.082atmL/molK*423.15K / 1.00L = 17.3 atm

Siendo las presiones en equilibrio:

P IBr: 17.3 - 2X

P I₂: X

P Br₂: X

Donde X representa el avance de reacción.

Remplazando en Keq:

280 = (17.3 - 2X)² / X²

280X² = 4X² - 69.2X + 299.29

0 = -276X² - 69.2X + 299.29

Resolviendo para X:

X = -1.174 → Solución falsa. No existen presiones negativas

X = 0.923 → Solución real

Así, las presiones parciales en equilibrio de cada compuesto son:

P IBr: 17.3 - 2X = 15.454atm

P I₂: X = 0.923atm

P Br₂: X = 0.923atm

3 0

3 years ago

Read 2 more answers

How do scientists know that the universe is expanding?

DanielleElmas [232]

Galaxies are moving away from us and the farther away a galaxy is the faster it is moving away from us. The galaxies seem to be receding from us because the entire universe is getting larger.

4 0

3 years ago

Read 2 more answers

Complete the table for ion charge based upon their losing or gaining electrons in the outer shell. (Use the periodic table as ne

PolarNik [594]

Answer:

Explanation:

Group one:

The elements of group one shows +1 charge because these all are metals and lose their one valance electron.

Hydrogen lithium sodium potassium rubidium cesium francium

Group 2:

The elements of group two shows +2 charge because these all alkali metals and lose their two valance electrons.

beryllium magnesium calcium strontium barium radium

Group 3:

The elements of group three-B shoes +3 charge by losing three valance electrons.

Scandium yttrium lanthanum actinium

Group 4:

The elements of group 4th A and 4th B lose four electrons or gain four electrons to complete the octet and shows +4 or -4 charge.

Group 5:

Group 5th elements gain three electrons and shows -3 charge to complete the 8 electrons. (octet).

It involve the elements of group 5th A.

Group 6:

The elements of group 6A gain two electrons to complete the octet and shows -2 charge.

Group 7:

The elements of group 7A gain one electron to complete the octet and shows -1 charge.

Group 8:

The elements of group 8A are noble gases and have complete octet. That's why shows 0 charge.

4 0

3 years ago

HNO3 + H2O > H3O(aq) + NO3-(aq)

Kruka [31]

What is the question and are there answers to go with it

8 0

3 years ago