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3 years ago

A gas station charges 1.299 per gallon of gas. What would be the price for a liter of gas?

Chemistry

1 answer:

Fudgin [204]3 years ago

5 0

Answer:

the price for a liter of gas will be of $ 0.3432

Explanation:

⇒ $ gas / L = $ 1.299 / Gal * ( Gal / 3.785 L )

⇒ $ gas / L = $ 0.3432 / L

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Answer would be A)the atom

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How many molecules are in 1.95 moles of water?

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Chromium(III) oxide can be prepared by heating chromium(IV) oxide in vacuo at high temperature: 4Cr02 —2Cr2O3 +02 The reaction o

kkurt [141]

<u>Answer:</u> The theoretical yield and percent yield of chromium (III) oxide is 434.72 grams and 92.6 % respectively.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

Given mass of $CrO_2$ = 480.1 g

Molar mass of $CrO_2$ = 84 g/mol

Putting values in equation 1, we get:

$\text{Moles of }CrO_2=\frac{480.1g}{84g/mol}=5.72mol$

For the given chemical equation:

$4CrO_2\rightarrow 2Cr_2O_3+O_2$

By Stoichiometry of the reaction:

4 moles of $CrO_2$ produces 2 moles of chromium (III) oxide

So, 5.72 moles of $CrO_2$ will produce = $\frac{2}{4}\times 5.72=2.86mol$ of chromium (III) oxide

Now, calculating the mass of chromium (III) oxide from equation 1, we get:

Molar mass of chromium (III) oxide = 152 g/mol

Moles of chromium (III) oxide = 2.86 moles

Putting values in equation 1, we get:

$2.86mol=\frac{\text{Mass of chromium (III) oxide}}{152g/mol}\\\\\text{Mass of chromium (III) oxide}=(2.86mol\times 152g/mol)=434.72g$

To calculate the percentage yield of chromium (III) oxide, we use the equation:

$\%\text{ yield}=\frac{\text{Experimental yield}}{\text{Theoretical yield}}\times 100$

Experimental yield of chromium (III) oxide = 402.4 g

Theoretical yield of chromium (III) oxide = 434.72 g

Putting values in above equation, we get:

$\%\text{ yield of chromium (III) oxide}=\frac{402.4g}{434.72g}\times 100\\\\\% \text{yield of chromium (III) oxide}=\%$

Hence, the theoretical yield and percent yield of chromium (III) oxide is 434.72 grams and 92.6 % respectively.

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3 years ago

What is the molar mass of Ba3(PO4)2?

Yakvenalex [24]

Answer:

<h3>explanation:</h3>

Problem: The Ba3(PO4)2 (molar mass = 601.93 g/mol) precipitate that formed from a salt mixture has a mass of 0.667 g.

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2 years ago

Martha ran 420 m, and Cole ran 60 m less than Martha. The distance Kate ran is right in the middle of Martha and Cole's distance

prohojiy [21]

Answer:

390 m

Explanation:

Martha ran 420 m

Cole ran 60 m less than Martha = 420 m - 60 m = 360 m

The distance Kate ran is right in the middle of Martha and Cole's distances

Kate distance = (420 + 360) / 2 = 780 / 2 = 390 m

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2 years ago