Answer:
The magnification is a function of the lenses in the objective and the eyepiece, so the magnification of the two must be multiplied to obtain the total magnification possible. So, for example, if the objective lens was 4X and the eye piece lens was 10X, the total magnification would be 40. (4 x 10 = 40)
Explanation:
Answer:
Explanation:
|F-->1| = E-->1 x charge on proton
= 300 x 1.6 x 10⁻¹⁹
Magnitude of electric force on proton
|F-->1| = 480 x 10⁻¹⁹ N .
Inside lithium nucleus , there are three protons so charge on it
= 3 x 1.6 x 10⁻¹⁹ = 4.8 x 10⁻¹⁹ C .
Magnitude of electric force on lithium nucleus
|F-->Li| = E-->1 x charge on lithium nucleus
= 300 x 4.8 x 10⁻¹⁹
= 1440 x 10⁻¹⁹ N .
Electron has same charge as that possessed by proton so charge on electron = 1.6 x 10⁻¹⁹ C
Magnitude of force on electron
|F-->1| = E-->1 x charge on electron
= 300 x 1.6 x 10⁻¹⁹
= 480 x 10⁻¹⁹ N .
Answer:
The kinetic energy of the baseball is 107.83 J
Explanation:
Given;
mass of the baseball, m = 144 g = 0.144 kg
velocity of the baseball, v = 38.7 m/s
The kinetic energy of the baseball is given by;
K.E = ¹/₂mv²
where;
m is mass of the object
v is speed of the object
K.E = ¹/₂(0.144)(38.7)²
K.E = 107.83 J
Therefore, the kinetic energy of the baseball is 107.83 J
Answer:
a. ![v_f=1.477m/s](https://tex.z-dn.net/?f=v_f%3D1.477m%2Fs)
b. Δ![K=1558.3J](https://tex.z-dn.net/?f=K%3D1558.3J)
c. ![E_k=1034.7 J](https://tex.z-dn.net/?f=E_k%3D1034.7%20J)
Explanation:
a).
Momentum conserved
![p_{ix}=p_{fx}](https://tex.z-dn.net/?f=p_%7Bix%7D%3Dp_%7Bfx%7D)
![m_1*v_1+m_2*v_2=(m_1+m_2)*v_f](https://tex.z-dn.net/?f=m_1%2Av_1%2Bm_2%2Av_2%3D%28m_1%2Bm_2%29%2Av_f)
![v_f=\frac{m_1*v_1+m_2*v_2}{m_1+m_2}](https://tex.z-dn.net/?f=v_f%3D%5Cfrac%7Bm_1%2Av_1%2Bm_2%2Av_2%7D%7Bm_1%2Bm_2%7D)
![v_f=\frac{89.0kg*5.6m/s+85.0kg*-2.84m/s}{(89.0+85.0)kg}](https://tex.z-dn.net/?f=v_f%3D%5Cfrac%7B89.0kg%2A5.6m%2Fs%2B85.0kg%2A-2.84m%2Fs%7D%7B%2889.0%2B85.0%29kg%7D)
![v_f=1.477m/s](https://tex.z-dn.net/?f=v_f%3D1.477m%2Fs)
b).
Δ![K=K_i-K_f](https://tex.z-dn.net/?f=K%3DK_i-K_f)
![\frac{1}{2}*m_1*v_1^2+\frac{1}{2}*m_2*v_2^2=\frac{1}{2}*(m_1+m_2)*v_f^2](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%2Am_1%2Av_1%5E2%2B%5Cfrac%7B1%7D%7B2%7D%2Am_2%2Av_2%5E2%3D%5Cfrac%7B1%7D%7B2%7D%2A%28m_1%2Bm_2%29%2Av_f%5E2)
![\frac{1}{2}*89.0kg*(5.6m/s)^2+\frac{1}{2}*85.0kg*(2.84m/s)^2=\frac{1}{2}*(89.0+85.0)kg*(1.447m/s)^2](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%2A89.0kg%2A%285.6m%2Fs%29%5E2%2B%5Cfrac%7B1%7D%7B2%7D%2A85.0kg%2A%282.84m%2Fs%29%5E2%3D%5Cfrac%7B1%7D%7B2%7D%2A%2889.0%2B85.0%29kg%2A%281.447m%2Fs%29%5E2)
Δ![K=1558.3J](https://tex.z-dn.net/?f=K%3D1558.3J)
c).
![E_k=\frac{1}{2}*89kg*(5.8m/s)^2-\frac{1}{2}*(85+89)kg*(1.44m/s)^2](https://tex.z-dn.net/?f=E_k%3D%5Cfrac%7B1%7D%7B2%7D%2A89kg%2A%285.8m%2Fs%29%5E2-%5Cfrac%7B1%7D%7B2%7D%2A%2885%2B89%29kg%2A%281.44m%2Fs%29%5E2)
![E_k=1034.7 J](https://tex.z-dn.net/?f=E_k%3D1034.7%20J)
d).
All of which has been lost as mechanical energy, and is now thermal energy warmer football players, noise a loud crunch for example.
To give the entire body oxygen so it has mechanical energy.