A 4000kg truck has a head-on inelastic collision with a 2500kg truck.
1 answer:
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Answer:
V₂ = 1.5 m/s
Explanation:
given,
speed of the first piece = 6 m/s
speed of the third piece = 3 m/s
speed of the second fragment = ?
mass ratios = 1 : 4 : 2
fragment break fly off = 120°
α = β = γ = 120°
sin α = sin β = sin γ = 0.866
using lammi's theorem
A,B and C is momentum of the fragments
4 x V₂ = 2 x 3
V₂ = 1.5 m/s
Answer:
Vf = 14 [m/s]
Explanation:
To solve this problem we must use the following equation of kinematics, which is independent of the mass of the object.
where:
Vf = final velocity [m/s]
Vo = initial velocity = 0
g = gravity acceleration = 9.81 [m/s²]
x = distance = 10 [m]
Now replacing:
Vf² = 0 + (2*9.81*10)
Vf = 14 [m/s]