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Answer:
The specific latent heat of a substance is the amount of energy required to change the state of one kilo of the substance without change in it temperature.The latent heat of vaporization or evaporation is the heat given to some mass to convert if from the liquid to the vapor phase.
Answer:
1.82 rad/s².
Explanation:
Applying,
α = (ω₂-ω₁)/t..................... Equation 1
Where α = angular acceleration of the fan blades, ω₂ = final angular velocity of the fan blades, ω₁ = initial angular velocity of the fan blades, t = time.
Given: ω₂ = 350 rpm = (350×0.1047) rad/s = 36.645 rad/s. ω₁ = 250 rpm = (250×0.1047) rad/s = 26.175 rad/s, t = 5.75 s.
Substitute into equation 1
α = (36.645-26.175)/5.75
α = 10.47/5.75
α = 1.82 rad/s².
Hence the magnitude of the angular acceleration of the fan blades = 1.82 rad/s²
Answer:
4541.8 J
Explanation:
First we find the mass of benzene available
mass = density x volume
= 0.867 x 34.1
= 29.5647 g
Then we find the amount of heat transferred by two processes:
heat tranferred = heat lost during temp drop + heat lost during freezing
= mcΔT + mL
= 29.5647 x 1.74 x (20.8 - 5.5) + 29.5647 x 127
= 4541.7883434 J
= 4541.8 J
