Answer:
Explanation:
<u>Dynamics of System of Masses</u>
We are given the characteristics of a system where two masses are connected by a massless string. The acceleration under these conditions is common to both objects. By analyzing the acting forces on each mass, we can find both the common acceleration and tension of the string.
Let's analyze the forces acting upon mass m1: To the right, we have the tension of the string that tries to move it in that direction. Opposite to the intent to move is the friction force to the left. Applying the Newton's second law, we have
Where
Thus
Now for the mass m2, in the vertical direction
Note that the sign of the acceleration is downwards since the mass m1 tends to move to the right and both masses are tied. W2 is the weight of the mass 2, thus
Replacing the value of T obtained above
Solving for a
Plugging in the given values:
Computing the tension of the string
Given parameters:
Displacement = 8km
Velocity = 3.8km/h
Unknown:
time = ?
Solution:
Velocity is displacement divided by time.
Velocity =
Displacement = velocity x time
Input the parameters:
8 = 3.8 x time
Time = = 2.1s
The time taken is 2.1s
Answer:
11.2m³
Explanation:
Applying Archimedes principle we have it that
Weight of submarine+ weight of tank+ weight of compound air =uptrust
So
(40000+2000+37V) x9.8= (30+V) 1030 x 9.8
38910= 993V
V= 11.2m³
Answer:
Explanation:
Given
mass of bullet
Length of barrel
Force
Work done
(b) When barrel is 1 m long
Answer:
hmmmmmmmm
Explanation:
mmmmmmmmmmmmmmmmmmmmmmm pay attention in class kid