Answer: Option B. 76.83L
Explanation:
1 mole of a gas occupy 22.4L at stp. This implies that 1mole of Radon also occupy 22.4L at stp.
If 1 mole of Radon = 22.4L
Therefore, 3.43 moles of Radon = 3.43 x 22.4 = 76.83L
You need to find the whole molar mass of the compound using the periodic table to add the values.
Na2CO3= (2 x 23.0) + 12.0 + (3 x 16.0)= 106 g/mol
H2O= 10 x [ (2 x 1.01 ) + (16.0) ]= 180.2 g/mol
the total molar mass is 106 + 180.2 = 286.2 g/mol
the percentage of water you can find by doing "parts over the whole"
H2O%= 180.2 / 286.2 X 100= 63.0%
Equation is as follow,
<span> 2 AgNO</span>₃<span> + MgBr</span>₂<span> </span>→ <span>2 AgBr + Mg(NO</span>₃<span>)</span>₂
According to eq.
339.74 g (2 moles) AgNO₃ produces = 375.54 g (2 moles) of AgBr
So,
22.5 g AgNO₃ will produce = X g of AgBr
Solving for X,
X = (22.5 g × 375.54 g) ÷ 339.74 g
X = 24.87 g of AgBr
Answer:
compounds are substance which can be formed by chemically combining two or more elements.
mixtures are substance that are formed by physically mixing two or more substances
