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2 years ago

What is the equation for the energy levels of the hydrogen atom

Chemistry

1 answer:

Kaylis [27]2 years ago

8 0

Answer: E = (13.6 eV) [1/nf² - 1/ni²]

En = (-13.6 eV)/n²

where n=1,2,3...

Explanation:

According to Bohr's theory each spcified energy value( E1,E2,E3...) is called energy level of the atom and the only allowable values are given by the equation

En = (-13.6 eV)/n²

The energy change (ΔE) that accompaies the leap of an electron from one energy level to another is given by equation

E = (13.6 eV) [1/nf² - 1/ni²]

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Question 6: The Ideal Gas Law (7 points) a. What is the mathematical equation for the ideal gas law? Identify each variable and

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The mathematical equation for the ideal gas law is PV = nRT.

<h3>What is an ideal gas equation?</h3>

The ideal gas law (PV = nRT) relates the macroscopic properties of ideal gases. An ideal gas is a gas in which the particles (a) do not attract or repel one another and (b) take up no space (have no volume).

(A)

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The ideal gas equation is formulated as: PV = nRT. In this equation, P refers to the pressure of the ideal gas, V is the volume of the ideal gas, n is the total amount of ideal gas that is measured in terms of moles, R is the universal gas constant, and T is the temperature.

(B)

Where the pressure - P, is in atmospheres (atm) the volume - V, is in liters (L) the moles -n, are in moles (m) and Temperature -T is in Kelvin (K) as in all gas law calculations.

(C)

A. Boyle's law

B. Charles's law

C. Avogadro's law

D. Dalton's law

____ $- P_1V_1$ = $P_2 V_2$

____ $\frac{V}{T}$ = k

____ $\frac{V_1}{T_1}$ = $\frac{V_2}{T_2}$

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Boyle's law $- P_1V_1$ = $P_2 V_2$

Charles's law - $\frac{V}{T}$ = K

Charles's law - $\frac{V_1}{T_1}$ = $\frac{V_2}{T_2}$

Avogadro's law- V = kn

Boyle's law - PV = k

Dalton's law - P total = $P_1 + P_2 + P_3 + ...$

Learn more about the ideal gas law here:

brainly.com/question/21353806

#SPJ1

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