Answer:
magnification = - 30
overall magnification = -240
Explanation:
given data
Focal length of microscope objective f = 0.150 cm
Object distance from microscope objective do = 0.155 cm
magnification by eyepiece = 8 ×
to find out
What magnification is produced and overall magnification
solution
we consider here Image distance from microscope objective is = di
so that
Magnification produced by objective will be = - 
so we find here di by given equation that is
..................1
di = 4.65 cm
so that magnification by object will be
magnification = -
magnification = - 
magnification = - 30
and
overall magnification will be
overall magnification = magnification by objective × magnification by eyepiece ........................2
overall magnification = -30 × 8
overall magnification = -240
1. D:Asteroids have geological activity
2.A:Short-period comets circle around the sun in 200 years or less and originate in the Kuiper Belt
3.D:All of the above
4.A:It’s gravity is too weak to clear it’s orbit
5.B:Ceres
6.C:Haumea
7.A:Is bigger than Pluto
I hope this helps
The expression of the magnetic force and solving the determinant allows to shorten the result for the value of the magnetic force are:
- In Cartesian form F = 2.46 i ^ - 0.605 j ^
- In the form of magnitude and direction F = 2.53 N and θ = 346.2º
Given parameters.
- Length of the wire on the z axis is: L = 25.0 cm = 0.25 m.
- The current i = 9.00 A in the positive direction of the z axis.
- The magnetic field B = (-0.242 i ^ - 0.985 j ^ -0.336 k ^ ) T
To find.
The magnetic force on a wire carrying a current is the vector product of the direction of the current and the magnetic field.
F = i L x B
Where the bold letters indicate vectors, F is the force, i the current, L a vector pointing in the direction of the current and B the magnetic field.
The best way to find the force is to solve the determinant, in general, a vector (L) is written in the form of the module times a <em>unit vector</em>.
![F= i |L| \left[\begin{array}{ccc}i&j&k\\L_x&L_y&L_z\\B_x&B_y&B_z\end{array}\right]](https://tex.z-dn.net/?f=F%3D%20i%20%7CL%7C%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Di%26j%26k%5C%5CL_x%26L_y%26L_z%5C%5CB_x%26B_y%26B_z%5Cend%7Barray%7D%5Cright%5D)
Let's calculate.
![F= 9.00 \ 0.25 \ \left[\begin{array}{ccc}i&j&k\\0&0&1\\-0.242&-0.985&-0.336\end{array}\right]](https://tex.z-dn.net/?f=F%3D%209.00%20%20%5C%200.25%20%5C%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Di%26j%26k%5C%5C0%260%261%5C%5C-0.242%26-0.985%26-0.336%5Cend%7Barray%7D%5Cright%5D)
F = 2.5 (0.985 i ^ - 0.242 j ^)
F = ( 2.46 i ^ - 0.605 j^ ) N
To find the magnitude we use the Pythagorean theorem.
F = 
F = 
F = 2.53 N
Let's use trigonometry for the direction.
Tan θ ’= 
θ'= tan⁻¹
θ'= tan⁻¹1 (
)
θ’= -13.8º
To measure this angle from the positive side of the x-axis counterclockwise.
θ = 360- θ'
θ = 360 - 13.8
θ = 346.2º
In conclusion using the expression of the magnetic force and solving the determinant we can shorten the result for the value of the force are:
- In Cartesian form F = 2.46 i ^ - 0.605 j ^
- In the form of magnitude and direction F = 2.53 N and θ = 346.2º
Learn more here: brainly.com/question/2630590
The original amount of the radioactive isotope will be 8 grams.
<h3 /><h3>What is the half-life of radioisotopes?</h3>
The amount of time required for half of a radioisotope's nuclide to decay, or change into a different species, is known as its half-life. The conversions release either beta or alpha particles, and the response can be monitored by counting the particles released.
Given that an unknown amount of a radioactive isotope with a half-life of 2.0 h was observed for 6.0 h. if the amount of the isotope remaining after 6.0 h was 24 g.
The original amount will be calculated as below:-
( 2 / 6 ) = ( Original amount / 24 )
Original amount = 4 x 2
Original amount = 8 grams
Therefore, the original amount of the radioactive isotope will be 8 grams.
To know more about the half-life of radioisotopes follow
brainly.com/question/1783783
#SPJ4
