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Alecsey [184]
2 years ago
8

Which of these actions requires KINETIC Energy? Choose all of the correct answers.

Physics
2 answers:
Keith_Richards [23]2 years ago
8 0

Answer:

turning a doorknob

Explanation:

it will snap back once you release it.

Harman [31]2 years ago
7 0

Answer:

- Turning a doorknob

- Swimming

- Hitting a tennis ball

Explanation:

Kinetic energy is the form of energy that an object or a particle has due to its motion (horizontal or vertical). An object gains kinetic energy when work is performed on it by putting a net force. This makes the object to speed up and acquire kinetic energy. Any object or particle that is moving is using kinetic energy

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a block weighing (Fg) 50 N is resting on a steel table (us = 0.74). The minimum force to start this block moving is what N
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Answer:37

Explanation:

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The figure below shows a man in a boat on a lake. The man's mass is 74 kg, and the boat's is 135 kg. The man and boat are initia
vazorg [7]

The velocity of the boat after the package is thrown is 0.36 m/s.

<h3>Final velocity of the boat</h3>

Apply the principle of conservation of linear momentum;

Pi = Pf

where;

  • Pi is initial momentum
  • Pf is final momentum

v(74 + 135) = 15 x 5

v(209) = 75

v = 75/209

v = 0.36 m/s

Thus, the velocity of the boat after the package is thrown is 0.36 m/s.

Learn more about velocity here: brainly.com/question/6504879

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7 0
2 years ago
This is an object's change in motion per unit time in a specified direction.
timurjin [86]

Answer:

Velocity

Explanation:

Velocity is an object's change in motion per unit time in a specified direction

7 0
3 years ago
Read 2 more answers
Which title best fits Rahma's note
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Answer:

diffusion is the answer.

4 0
3 years ago
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A certain reaction with an activation energy of 185 kJ/mol was run at 525 K and again at 545 K . What is the ratio of f at the h
Kazeer [188]

Answer: The ratio of f at the higher temperature to f at the lower temperature is 4.736

Explanation:

According to the Arrhenius equation,

f=A\times e^{\frac{-Ea}{RT}}

or,

\log (\frac{f_2}{f_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]

where,

f_1 = rate constant at 525K

K_2 = rate constant at 545K

Ea = activation energy for the reaction = 185kJ/mol= 185000J/mol   (1kJ=1000J)

R = gas constant = 8.314 J/mole.K

T_1 = initial temperature = 525 K

T_2 = final temperature = 545 K

Now put all the given values in this formula, we get

\log (\frac{f_2}{f_1})=\frac{185000J/mol}{2.303\times 8.314J/mole.K}[\frac{1}{525K}-\frac{1}{545K}]

\log (\frac{f_2}{f_1})=0.6754

(\frac{f_2}{f_1})=4.736

Therefore, the ratio of f at the higher temperature to f at the lower temperature is 4.736

8 0
3 years ago
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